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The chances of A, B, C becoming managers of a Testbook company are 4:2:3. The probability that the bonus scheme will be introduced if A, B, C become manager are 0.3, 0.5, 0.8 respectively.
If the bonus scheme has introduced, what is the probability that A is appointed as the manager of Testbook (answer up to 2 decimal place)?
    Correct answer is between '0.26,0.27'. Can you explain this answer?
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    The chances of A, B, C becoming managers of a Testbook company are 4:2...
    P(X)→ probability that bonus scheme is introduced
    P(A) → probability of A being a manager.

    P(B) → probability of B being a manager.

    P(C) → probability of C being a manager.
    P(X) = P (A ∩ X) + P (B ∩ X) + P (C ∩ X)
    P(X) = P(A)P(X/A) + P(B)P(X/B) + P(C)P(X/C)
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    The chances of A, B, C becoming managers of a Testbook company are 4:2...
    Problem: The chances of A, B, C becoming managers of a Testbook company are 4:2:3. The probability that the bonus scheme will be introduced if A, B, C become manager are 0.3, 0.5, 0.8 respectively. If the bonus scheme has introduced, what is the probability that A is appointed as the manager of Testbook (answer up to 2 decimal places)?

    Solution:

    Step 1: Calculate the probability of A, B, C becoming managers of Testbook company.

    Total chances = 4 + 2 + 3 = 9

    Probability of A becoming the manager = 4/9
    Probability of B becoming the manager = 2/9
    Probability of C becoming the manager = 3/9

    Step 2: Calculate the probability of the bonus scheme being introduced if A, B, C become managers.

    Probability of the bonus scheme being introduced if A becomes the manager = 0.3
    Probability of the bonus scheme being introduced if B becomes the manager = 0.5
    Probability of the bonus scheme being introduced if C becomes the manager = 0.8

    Step 3: Calculate the probability of A being appointed as the manager of Testbook company if the bonus scheme is introduced.

    Probability of the bonus scheme being introduced = Probability of A becoming the manager * Probability of bonus scheme being introduced if A becomes the manager

    = (4/9) * 0.3

    = 0.1333

    Probability of B becoming the manager * Probability of bonus scheme being introduced if B becomes the manager = (2/9) * 0.5 = 0.1111

    Probability of C becoming the manager * Probability of bonus scheme being introduced if C becomes the manager = (3/9) * 0.8 = 0.2667

    Step 4: Calculate the probability of A being appointed as the manager of Testbook company if the bonus scheme is introduced.

    Probability of A being appointed as the manager if the bonus scheme is introduced = Probability of A becoming the manager and the bonus scheme being introduced / Probability of the bonus scheme being introduced

    = 0.1333 / (0.1333 + 0.1111 + 0.2667)

    = 0.2666

    Step 5: Round off the answer up to 2 decimal places.

    Therefore, the probability of A being appointed as the manager of Testbook company if the bonus scheme is introduced is 0.27 (approx).
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    The chances of A, B, C becoming managers of a Testbook company are 4:2:3. The probability that the bonus scheme will be introduced if A, B, C become manager are 0.3, 0.5, 0.8 respectively.If the bonus scheme has introduced, what is the probability that A is appointed as the manager of Testbook (answer up to 2 decimal place)?Correct answer is between '0.26,0.27'. Can you explain this answer?
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