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What is [H+] in mol/L of a solution that is 0.20 M in CH3COONa and 0.10 M in CH3COOH?Ka for CH3COOH = 1.8 × 10-5 . [2010]
- a)3.5 × 10-4
- b)1.1 × 10-5
- c)1.8 × 10-5
- d)9.0 × 10-6
Correct answer is option 'D'. Can you explain this answer?
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What is [H+] in mol/L of a solution that is 0.20 M in CH3COONa and 0.1...
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What is [H+] in mol/L of a solution that is 0.20 M in CH3COONa and 0.1...
To find the concentration of H+ ions in the solution, we need to consider the dissociation of CH3COOH in water. The dissociation reaction is as follows:
CH3COOH + H2O ⇌ CH3COO- + H3O+
We are given the concentrations of CH3COONa and CH3COOH, but we need to find the concentration of H+ ions. We can use the equilibrium constant expression for the dissociation of CH3COOH to calculate this:
Ka = [CH3COO-][H3O+]/[CH3COOH]
Since CH3COONa is a salt, it completely dissociates in water, and the concentration of CH3COO- ions is equal to the concentration of CH3COONa. Therefore, [CH3COO-] = 0.20 M.
Let's assume [H3O+] = [H+]. Therefore, [H+] = x (where x is the concentration of H+ ions).
Substituting the given values into the equilibrium constant expression:
1.8 = (0.20 M)(x)/(0.10 M)
Simplifying the equation:
1.8 = 2x
x = 1.8/2
x = 0.90 M
Therefore, the concentration of H+ ions, [H+], in the solution is 0.90 M.
CH3COOH + H2O ⇌ CH3COO- + H3O+
We are given the concentrations of CH3COONa and CH3COOH, but we need to find the concentration of H+ ions. We can use the equilibrium constant expression for the dissociation of CH3COOH to calculate this:
Ka = [CH3COO-][H3O+]/[CH3COOH]
Since CH3COONa is a salt, it completely dissociates in water, and the concentration of CH3COO- ions is equal to the concentration of CH3COONa. Therefore, [CH3COO-] = 0.20 M.
Let's assume [H3O+] = [H+]. Therefore, [H+] = x (where x is the concentration of H+ ions).
Substituting the given values into the equilibrium constant expression:
1.8 = (0.20 M)(x)/(0.10 M)
Simplifying the equation:
1.8 = 2x
x = 1.8/2
x = 0.90 M
Therefore, the concentration of H+ ions, [H+], in the solution is 0.90 M.
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What is [H+] in mol/L of a solution that is 0.20 M in CH3COONa and 0.10 M in CH3COOH?Ka for CH3COOH = 1.8 × 10-5 . [2010]a)3.5 × 10-4b)1.1 × 10-5c)1.8 × 10-5d)9.0 × 10-6Correct answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about What is [H+] in mol/L of a solution that is 0.20 M in CH3COONa and 0.10 M in CH3COOH?Ka for CH3COOH = 1.8 × 10-5 . [2010]a)3.5 × 10-4b)1.1 × 10-5c)1.8 × 10-5d)9.0 × 10-6Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is [H+] in mol/L of a solution that is 0.20 M in CH3COONa and 0.10 M in CH3COOH?Ka for CH3COOH = 1.8 × 10-5 . [2010]a)3.5 × 10-4b)1.1 × 10-5c)1.8 × 10-5d)9.0 × 10-6Correct answer is option 'D'. Can you explain this answer?.
What is [H+] in mol/L of a solution that is 0.20 M in CH3COONa and 0.10 M in CH3COOH?Ka for CH3COOH = 1.8 × 10-5 . [2010]a)3.5 × 10-4b)1.1 × 10-5c)1.8 × 10-5d)9.0 × 10-6Correct answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about What is [H+] in mol/L of a solution that is 0.20 M in CH3COONa and 0.10 M in CH3COOH?Ka for CH3COOH = 1.8 × 10-5 . [2010]a)3.5 × 10-4b)1.1 × 10-5c)1.8 × 10-5d)9.0 × 10-6Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is [H+] in mol/L of a solution that is 0.20 M in CH3COONa and 0.10 M in CH3COOH?Ka for CH3COOH = 1.8 × 10-5 . [2010]a)3.5 × 10-4b)1.1 × 10-5c)1.8 × 10-5d)9.0 × 10-6Correct answer is option 'D'. Can you explain this answer?.
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