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A 5m high vertical earth retaining wall having smooth vertical back retains non-cohesive soil with angle of internal friction 35° and unit weight γ = 18 kN/m3. If the wall is free to field and the water table is at a depth of 2m below the top of the wall, then the total horizontal active thrust (kN) per unit length acting on the wall will be
Take γsat = 20 kN/m3, γω = 10kN/m3.
  • a)
    96.221 kN/m
  • b)
    86.46 kN/m
  • c)
    108.416 kN/m
  • d)
    120 kN/m
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A 5m high vertical earth retaining wall having smooth vertical back re...

Total active earth pressure at 2m below the Ground level = kaγ×2

Active thrust:
Pa1 = 12 × ka × γ × 2 × 2 = 
Pa1 = 9.756 kN/m
Total active earth pressure at 5m below the Ground level:
= ka × γ ×2 + kaγ1×3 + γω × 3
= 0.271 × 18 × 2 + 0.271 × [20 – 10] × 3 + 10 × 3
= 47.88 kN/m2

Active thrust:-

Pa = 9.756 + 29.27 + 12.195 + 45
Pa = 96.221 kN/m
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Most Upvoted Answer
A 5m high vertical earth retaining wall having smooth vertical back re...
Degrees. The unit weight of the soil is 16 kN/m3. Determine the active and passive pressures on the retaining wall.

Solution:

Given:
Height of retaining wall (h) = 5m
Angle of internal friction (φ) = 35 degrees
Unit weight of soil (γ) = 16 kN/m3

To determine the active and passive pressures on the retaining wall, we need to consider two cases:

Case 1: When the soil is at rest

The lateral earth pressure coefficient, K0 = 1 - sin φ

K0 = 1 - sin 35
K0 = 0.427

The vertical stress at the bottom of the wall, σv = γh

σv = 16 x 5
σv = 80 kN/m2

The lateral earth pressure, P = K0 σv

P = 0.427 x 80
P = 34.16 kN/m2

The active pressure is given by Pa = 0.5P

Pa = 0.5 x 34.16
Pa = 17.08 kN/m2

Case 2: When the soil is fully mobilized

The lateral earth pressure coefficient, Kp = 1 + sin φ

Kp = 1 + sin 35
Kp = 1.573

The passive pressure is given by Pp = Kp σv

Pp = 1.573 x 80
Pp = 125.84 kN/m2

Therefore, the active pressure on the retaining wall is 17.08 kN/m2 and the passive pressure is 125.84 kN/m2.
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A 5m high vertical earth retaining wall having smooth vertical back retains non-cohesive soil with angle of internal friction 35° and unit weight γ = 18 kN/m3. If the wall is free to field and the water table is at a depth of 2m below the top of the wall, then the total horizontal active thrust (kN) per unit length acting on the wall will beTake γsat= 20 kN/m3, γω= 10kN/m3.a)96.221 kN/mb)86.46 kN/mc)108.416 kN/md)120 kN/mCorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A 5m high vertical earth retaining wall having smooth vertical back retains non-cohesive soil with angle of internal friction 35° and unit weight γ = 18 kN/m3. If the wall is free to field and the water table is at a depth of 2m below the top of the wall, then the total horizontal active thrust (kN) per unit length acting on the wall will beTake γsat= 20 kN/m3, γω= 10kN/m3.a)96.221 kN/mb)86.46 kN/mc)108.416 kN/md)120 kN/mCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5m high vertical earth retaining wall having smooth vertical back retains non-cohesive soil with angle of internal friction 35° and unit weight γ = 18 kN/m3. If the wall is free to field and the water table is at a depth of 2m below the top of the wall, then the total horizontal active thrust (kN) per unit length acting on the wall will beTake γsat= 20 kN/m3, γω= 10kN/m3.a)96.221 kN/mb)86.46 kN/mc)108.416 kN/md)120 kN/mCorrect answer is option 'A'. Can you explain this answer?.
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