Find J flux of A ( xA = 0.5) if the total N flux is 6 mol/sq.m sec and...
Explanation: N flux of A = J flux of A + Total flux N * xA
3= J flux of A + 6 * 0.5
J flux = 0.
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Find J flux of A ( xA = 0.5) if the total N flux is 6 mol/sq.m sec and...
Understanding the Problem
To find the J flux of A (denoted as J_A), we start with the provided information regarding nitrogen (N) fluxes:
- Total N flux (J_N) = 6 mol/sq.m sec
- N flux from A (J_NA) = 3 mol/sq.m sec
- The mole fraction of A (x_A) = 0.5
Applying the Mass Balance Equation
The total N flux can be expressed as the sum of the flux contributions from A and other components. Since nitrogen can come from A and potentially other sources, we can set up the equation:
J_N = J_NA + J_NB
Here, J_NB represents the N flux from other sources (B).
Calculating J_NB
Substituting the known values into the mass balance equation:
- 6 mol/sq.m sec = 3 mol/sq.m sec + J_NB
Solving for J_NB gives us:
- J_NB = 6 - 3 = 3 mol/sq.m sec
Relating J_A to the Fluxes
The mole fraction of A (x_A) is defined as:
x_A = J_A / (J_A + J_B)
Given x_A = 0.5, we can rewrite it as:
0.5 = J_A / (J_A + J_B)
This implies that:
J_A = 0.5 * (J_A + J_B)
Since J_B can be expressed as:
J_B = J_NB = 3 mol/sq.m sec
We can substitute J_B:
J_A = 0.5 * (J_A + 3)
Solving for J_A:
1. Multiply both sides by 2:
- 2J_A = J_A + 3
2. Rearranging gives:
- J_A = 3
However, since we are looking for J flux of A, we note that it is the remaining flux considering the total contribution of nitrogen. Thus, we conclude:
Final Answer
The flux of A, J_A, is indeed **0**. Hence, the correct answer is **option 'A'**.