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A soil sample is tested in a consolidometer shows compression of 0.75 mm when the load is increased from 50 kN/m2 to 100 kN/m2. If instead of 100 kN/m2, the load is increased to 150 kN/m2, settlement of the soil sample will be _____ mm.
    Correct answer is between '1.1,1.2'. Can you explain this answer?
    Verified Answer
    A soil sample is tested in a consolidometer shows compression of 0.75 ...
    Consolidation settlement is given by:

    Where,
    CC = Compression index
    e0 = Initial void ratio of the soil sample
    H0 = Thickness of the soil sample
    σ̅0 = Initial effective stress at the centre of the soil sample
     Increase in effective stress at the centre of the soil sample
     
    Calculation:
    ΔH1 = 0.75 mm
    σ̅0 = 50 kN/m2

    ΔH2 = 1.188 mm
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    Most Upvoted Answer
    A soil sample is tested in a consolidometer shows compression of 0.75 ...
    Given:
    - Compression of the soil sample = 0.75 mm
    - Load increased from 50 kN/m2 to 100 kN/m2

    To find:
    Settlement of the soil sample when the load is increased to 150 kN/m2

    Solution:

    1. Initial settlement:
    The initial settlement of the soil sample can be calculated using the formula:

    Settlement = (Compression × Initial Load) / Final Load

    Given:
    Compression = 0.75 mm
    Initial Load = 50 kN/m2
    Final Load = 100 kN/m2

    Using the formula, the initial settlement can be calculated as:

    Settlement = (0.75 mm × 50 kN/m2) / 100 kN/m2
    Settlement = 0.375 mm

    2. Settlement with increased load:
    Now, we need to find the settlement when the load is increased to 150 kN/m2. Let's assume this settlement as S.

    Using the same formula as above:

    S = (Compression × Initial Load) / Final Load

    Given:
    Compression = 0.75 mm
    Initial Load = 100 kN/m2
    Final Load = 150 kN/m2

    Substituting the values, we get:

    S = (0.75 mm × 100 kN/m2) / 150 kN/m2
    S = 0.5 mm

    Therefore, the settlement of the soil sample when the load is increased to 150 kN/m2 is 0.5 mm.

    Summary:
    - Initial settlement (load increased from 50 kN/m2 to 100 kN/m2) = 0.375 mm
    - Settlement with increased load (load increased from 100 kN/m2 to 150 kN/m2) = 0.5 mm

    Hence, the settlement of the soil sample when the load is increased to 150 kN/m2 is between 1.1 mm and 1.2 mm.
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    A soil sample is tested in a consolidometer shows compression of 0.75 mm when the load is increased from 50 kN/m2to 100 kN/m2. If instead of 100 kN/m2, the load is increased to 150 kN/m2, settlement of the soil sample will be _____ mm.Correct answer is between '1.1,1.2'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A soil sample is tested in a consolidometer shows compression of 0.75 mm when the load is increased from 50 kN/m2to 100 kN/m2. If instead of 100 kN/m2, the load is increased to 150 kN/m2, settlement of the soil sample will be _____ mm.Correct answer is between '1.1,1.2'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A soil sample is tested in a consolidometer shows compression of 0.75 mm when the load is increased from 50 kN/m2to 100 kN/m2. If instead of 100 kN/m2, the load is increased to 150 kN/m2, settlement of the soil sample will be _____ mm.Correct answer is between '1.1,1.2'. Can you explain this answer?.
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