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A lake of depth 15 m is filled with water up to a depth of 10 m from the Bottom of the lake. Soft clay is present below the bottom of the lake up to a certain depth of more than 20 m. Submerged unit weight of the clay is given as 9.5 kN/m3. Take γw = 10 kN/m3. Calculate the effective Stress (kN/m2) at a depth of 15 m below the bottom of the lake.
    Correct answer is between '142,143'. Can you explain this answer?
    Verified Answer
    A lake of depth 15 m is filled with water up to a depth of 10 m from t...

    γ’ = γsat - γw
    γsat = γ’ + γ= 9.5 + 10 = 19.5 kN/m3
    σ’ = σ - u
    At at depth of 15 m below lake
    σ = γ× 10 + γsat × 15
    σ = 10 × 10 + 19.5 × 15
    σ = 392.5 kw/m2
    u = 25 × γw = 25 × 10 = 250 kN/m2
    = σ - 4
    = 392.5 - 250
    = 142.5 kN/m2
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    Most Upvoted Answer
    A lake of depth 15 m is filled with water up to a depth of 10 m from t...
    Understanding Effective Stress
    Effective stress is crucial in soil mechanics, representing the stress carried by the soil skeleton. It is calculated using the formula:
    Effective Stress = Total Stress - Pore Water Pressure
    Calculation Steps
    1. Determine Total Stress at 15 m Depth
    - The total depth of 15 m is measured from the bottom of the lake, which means we need to consider the water depth and the depth of the clay below.
    - The water column exerts pressure calculated as:
    Total Stress (σ) = (Depth of water) * γw
    = 10 m * 10 kN/m³ = 100 kN/m²
    2. Depth of Clay Below the Lake
    - The clay extends beyond the lake's bottom, reaching at least 20 m depth, totaling 15 m depth from the lake's bottom down to the clay.
    - Therefore, we consider the pressure due to the clay weight as well:
    Total Stress from clay (σ_clay) = (Depth of clay) * γ_clay
    = 15 m * 9.5 kN/m³ = 142.5 kN/m²
    3. Calculate Total Stress
    - Combine both contributions:
    Total Stress = σ + σ_clay
    = 100 kN/m² + 142.5 kN/m² = 242.5 kN/m²
    4. Calculate Pore Water Pressure
    - The pore water pressure at this depth is calculated using the submerged unit weight of the clay:
    Pore Water Pressure (u) = Depth * γw
    = 15 m * 10 kN/m³ = 150 kN/m²
    5. Calculate Effective Stress
    - Finally, use the effective stress formula:
    Effective Stress (σ') = Total Stress - Pore Water Pressure
    = 242.5 kN/m² - 150 kN/m² = 92.5 kN/m²
    Conclusion
    The effective stress at a depth of 15 m below the lake is approximately 92.5 kN/m² and does not align with the expected range of 142-143 kN/m². Thus, ensure to verify the depth and unit weights are accurately represented for precise calculations.
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    A lake of depth 15 m is filled with water up to a depth of 10 m from the Bottom of the lake. Soft clay is present below the bottom of the lake up to a certain depth of more than 20 m. Submerged unit weight of the clay is given as 9.5 kN/m3. Take γw= 10 kN/m3. Calculate the effective Stress (kN/m2) at a depth of 15 m below the bottom of the lake.Correct answer is between '142,143'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A lake of depth 15 m is filled with water up to a depth of 10 m from the Bottom of the lake. Soft clay is present below the bottom of the lake up to a certain depth of more than 20 m. Submerged unit weight of the clay is given as 9.5 kN/m3. Take γw= 10 kN/m3. Calculate the effective Stress (kN/m2) at a depth of 15 m below the bottom of the lake.Correct answer is between '142,143'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A lake of depth 15 m is filled with water up to a depth of 10 m from the Bottom of the lake. Soft clay is present below the bottom of the lake up to a certain depth of more than 20 m. Submerged unit weight of the clay is given as 9.5 kN/m3. Take γw= 10 kN/m3. Calculate the effective Stress (kN/m2) at a depth of 15 m below the bottom of the lake.Correct answer is between '142,143'. Can you explain this answer?.
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