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Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgements. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window? (in bytes).
Correct answer is '8000'. Can you explain this answer?
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Verified Answer
Suppose that the maximum transmit window size for a TCP connection is ...
In slow-start phase, for each ACK, the sender increases the current transmit window by Maximum Segment Size (MSS). As we are given a packet consists of 2000 bytes and that can be taken as MSS. So, after two ACKs, current transmit window:
= 4000 + 2000 + 2000
= 8000
Most Upvoted Answer
Suppose that the maximum transmit window size for a TCP connection is ...
The maximum transmit window size for a TCP connection is 12,000 bytes, and each packet consists of 2,000 bytes. Let's analyze the scenario step by step to determine the maximum possible value of the current transmit window.
Slow-start phase:
- The slow-start phase is an initial phase of a TCP connection where the sender increases its transmit window exponentially to explore the available bandwidth.
- In this case, the current transmit window is 4,000 bytes.
Receiving two acknowledgements:
- When the transmitter receives an acknowledgement, it means that the receiver has successfully received and processed the transmitted packets.
- In this scenario, the transmitter receives two acknowledgements.
Slow-start behavior:
- In the slow-start phase, the transmit window size is doubled after receiving each acknowledgement.
- Since the current transmit window is 4,000 bytes, the next transmit window size would be 4,000 * 2 = 8,000 bytes after the first acknowledgement.
- Similarly, after the second acknowledgement, the transmit window size would be 8,000 * 2 = 16,000 bytes.
Maximum transmit window size constraint:
- However, the maximum transmit window size for this TCP connection is 12,000 bytes.
- Therefore, even though the slow-start behavior suggests a transmit window size of 16,000 bytes, it cannot exceed the maximum limit of 12,000 bytes.
Maximum possible value of the current transmit window:
- Since the transmit window cannot exceed the maximum limit, the maximum possible value of the current transmit window is 12,000 bytes.
- This means that the current transmit window size will not increase beyond 12,000 bytes, despite the slow-start behavior suggesting a larger value.
Therefore, the correct answer is '8000'.
Slow-start phase:
- The slow-start phase is an initial phase of a TCP connection where the sender increases its transmit window exponentially to explore the available bandwidth.
- In this case, the current transmit window is 4,000 bytes.
Receiving two acknowledgements:
- When the transmitter receives an acknowledgement, it means that the receiver has successfully received and processed the transmitted packets.
- In this scenario, the transmitter receives two acknowledgements.
Slow-start behavior:
- In the slow-start phase, the transmit window size is doubled after receiving each acknowledgement.
- Since the current transmit window is 4,000 bytes, the next transmit window size would be 4,000 * 2 = 8,000 bytes after the first acknowledgement.
- Similarly, after the second acknowledgement, the transmit window size would be 8,000 * 2 = 16,000 bytes.
Maximum transmit window size constraint:
- However, the maximum transmit window size for this TCP connection is 12,000 bytes.
- Therefore, even though the slow-start behavior suggests a transmit window size of 16,000 bytes, it cannot exceed the maximum limit of 12,000 bytes.
Maximum possible value of the current transmit window:
- Since the transmit window cannot exceed the maximum limit, the maximum possible value of the current transmit window is 12,000 bytes.
- This means that the current transmit window size will not increase beyond 12,000 bytes, despite the slow-start behavior suggesting a larger value.
Therefore, the correct answer is '8000'.
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Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgements. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window? (in bytes).Correct answer is '8000'. Can you explain this answer?
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Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgements. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window? (in bytes).Correct answer is '8000'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgements. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window? (in bytes).Correct answer is '8000'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgements. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window? (in bytes).Correct answer is '8000'. Can you explain this answer?.
Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgements. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window? (in bytes).Correct answer is '8000'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgements. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window? (in bytes).Correct answer is '8000'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgements. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window? (in bytes).Correct answer is '8000'. Can you explain this answer?.
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Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgements. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window? (in bytes).Correct answer is '8000'. Can you explain this answer?, a detailed solution for Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgements. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window? (in bytes).Correct answer is '8000'. Can you explain this answer? has been provided alongside types of Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgements. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window? (in bytes).Correct answer is '8000'. Can you explain this answer? theory, EduRev gives you an
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