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Which is the most suitable reagent among the following to distinguish compound (3) from rest of the compounds ? [1989]
  • a)
    Bromine in carbon tetrachloride
  • b)
    Bromine in acetic acid
  • c)
    Alk KMnO4
  • d)
    Ammonical silver nitrate.
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Which is the most suitable reagent among the following to distinguish ...
Br2 in CCl4 (a), Br2 in CH3 COOH (b) and alk.
KMnO4 (c) will react with all unsaturated compounds, i.e., 1, 3 and 4 while ammonical AgNO3 (d) reacts only with terminal alkynes, i.e., 3 and hence compund 3 can be distinguished from 1, 2 and 4 by. ammonical AgNO3 (d).
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Which is the most suitable reagent among the following to distinguish compound (3) from rest of the compounds ? [1989]a)Bromine in carbon tetrachlorideb)Bromine in acetic acidc)Alk KMnO4d)Ammonical silver nitrate.Correct answer is option 'D'. Can you explain this answer?
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Which is the most suitable reagent among the following to distinguish compound (3) from rest of the compounds ? [1989]a)Bromine in carbon tetrachlorideb)Bromine in acetic acidc)Alk KMnO4d)Ammonical silver nitrate.Correct answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Which is the most suitable reagent among the following to distinguish compound (3) from rest of the compounds ? [1989]a)Bromine in carbon tetrachlorideb)Bromine in acetic acidc)Alk KMnO4d)Ammonical silver nitrate.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which is the most suitable reagent among the following to distinguish compound (3) from rest of the compounds ? [1989]a)Bromine in carbon tetrachlorideb)Bromine in acetic acidc)Alk KMnO4d)Ammonical silver nitrate.Correct answer is option 'D'. Can you explain this answer?.
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