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The product formed in Aldol condensation is       [2007]
  • a)
    a beta-hydroxy aldehyde or a beta-hydroxyketone
  • b)
    an alpha-hydroxy aldehyde or ketone
  • c)
    an alpha, beta unsaturated ester
  • d)
    a beta-hydroxy acid
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The product formed in Aldol condensation is [2007]a)a beta-hydroxy a...
Aldehydes and ketones having at least one
α-hydrogen atom in presence of dilute
alkali give β-hydroxy aldehyde or β-
hydroxy ketone
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Most Upvoted Answer
The product formed in Aldol condensation is [2007]a)a beta-hydroxy a...

Explanation:

Aldol condensation:
- Aldol condensation is a reaction that involves the formation of a beta-hydroxy aldehyde or a beta-hydroxyketone through the reaction of two carbonyl compounds.
- The reaction typically involves an aldehyde or ketone reacting with itself under basic conditions to form the desired product.

Product formed:
- The product formed in Aldol condensation is a beta-hydroxy aldehyde or a beta-hydroxyketone.
- This occurs when the alpha carbon of one carbonyl compound adds to the carbonyl carbon of another, followed by elimination of water to form a new carbon-carbon bond.

Specific products:
- If the carbonyl compounds involved are aldehydes, the product will be a beta-hydroxy aldehyde.
- If the carbonyl compounds involved are ketones, the product will be a beta-hydroxyketone.

Conclusion:
- Therefore, the correct answer to the question is option 'A', which states that the product formed in Aldol condensation is a beta-hydroxy aldehyde or a beta-hydroxyketone.
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Read the passage given below and answer the following questions:Reductive alkylation is the term applied to the process of introducing alkyl groups into ammonia or a primary or secondary amine by means of an aldehyde or ketone in the presence of a reducing agent. The present discussion is limited to those reductive alkylations in which the reducing agent is hydrogen and a catalyst or "nascent" hydrogen, usually from a metalacid combination; most of these reductive alkylations have been carried out with hydrogen and a catalyst. The principal variation excluded is that in which the reducing agent is formic acid or one of its derivatives; this modification is known as the Leuckart reaction. The process of reductive alkylation of ammonia consists in the addition of ammonia to a carbonyl compound and reduction of the addition compound or its dehydration product. The reaction usually is carried out in ethanol solution when the reduction is to be effected catalytically:Since the primary amine is formed in the presence of the aldehyde it may react in the same way as ammonia, yielding an additional compound, a Schiff's base (RCH= NCH2R) and finally, a secondary amine. Similarly, the primary amine may react with the imine, forming an addition product which also is reduced to a secondary amine Finally, the secondary amine may react with either the aldehyde or the imine to give products which are reduced to tertiary amines.Similar reactions may occur when the carbonyl compound employed is a ketone.Q. The reaction of ammonia and its derivatives with aldehydes is called

The product formed in Aldol condensation is [2007]a)a beta-hydroxy aldehyde or a beta-hydroxyketoneb)an alpha-hydroxy aldehyde or ketonec)an alpha, beta unsaturated esterd)a beta-hydroxy acidCorrect answer is option 'A'. Can you explain this answer?
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