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Consider the following code which is used to detect the loop in the linked list. Find the missing statement A?
p = head;
q = head->next;
while(A)
{
    if(p == q) exit(0) //loop detected
    p = p->next;
    q = (q->next)?(q->next->next) : q->next;
}
  • a)
    (p!=NULL) || (q!=NULL)
  • b)
    p!=NULL
  • c)
    q!=NULL
  • d)
    (p!=NULL) && (q!=NULL)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Consider the following code which is used to detect the loop in the li...
q will go end of list first and will accept
q==NULL and will terminate.
Otherwise p and q both get a valid pointer value and keep moving.
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Most Upvoted Answer
Consider the following code which is used to detect the loop in the li...
There seems to be a mistake in the statement provided. It is cut off and does not form a complete code snippet. In order to provide a missing statement, the complete code snippet is required.
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