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A transmission line having open circuit impedance and short circuit impedance parameters are respectively  Zoc = 900∠ − 30, ZSC = 400∠30∘ , Find the characteristic impedance of the line – (in Ω)
    Correct answer is '600'. Can you explain this answer?
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    Ω and Zsc = 45 Ω. The characteristic impedance of the line is given by:

    Z0 = sqrt(Zoc * Zsc) = sqrt(900 * 45) = 300 Ω

    The propagation constant of the line is given by:

    γ = sqrt((Zoc/Zsc) - 1) = sqrt((900/45) - 1) = sqrt(19)

    The phase velocity of the line is given by:

    vp = ω/γ = c/sqrt(1 + Zoc/Zsc) = c/sqrt(1 + 900/45) = c/7

    where c is the speed of light in vacuum. Therefore, the phase velocity of the line is approximately 42.9% of the speed of light.
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    A transmission line having open circuit impedance and short circuit impedance parameters are respectively Zoc = 900∠ − 30∘, ZSC = 400∠30∘, Find the characteristic impedance of the line – (in Ω)Correct answer is '600'. Can you explain this answer?
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