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A sedimentation tank is treating 2 MLD of sewage per day containing 225 mg/L of suspended solids. The tank removes 30% of suspended solids. The moisture content of sludge is 98%. If the sludge is reduced to half of its volume, then the moisture content of the reduced volume sludge is –
  • a)
    92%
  • b)
    95%
  • c)
    94%
  • d)
    96%
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A sedimentation tank is treating 2 MLD of sewage per day containing 22...

 
⇒ 100 – P = 2 × 2
⇒ P = 100 – 4
⇒ P = 96%
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A sedimentation tank is treating 2 MLD of sewage per day containing 22...
To find the amount of suspended solids removed by the sedimentation tank per day, we can use the formula:

Amount of suspended solids removed = Flow rate of sewage (MLD) * Concentration of suspended solids (mg/L) * Removal efficiency

Amount of suspended solids removed = 2 MLD * 225 mg/L * 0.30 = 135 mg/day

The moisture content of the sludge is given as 98%. This means that 98% of the sludge is moisture and the remaining 2% is solids.

If the sludge is reduced to half of its volume, the moisture content will remain the same at 98% because the ratio of moisture to solids remains constant. The reduction in volume does not affect the moisture content.

Therefore, the moisture content of the reduced volume sludge will still be 98%.
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A sedimentation tank is treating 2 MLD of sewage per day containing 225 mg/L of suspended solids. The tank removes 30% of suspended solids. The moisture content of sludge is 98%. If the sludge is reduced to half of its volume, then the moisture content of the reduced volume sludge is –a)92%b)95%c)94%d)96%Correct answer is option 'D'. Can you explain this answer?
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A sedimentation tank is treating 2 MLD of sewage per day containing 225 mg/L of suspended solids. The tank removes 30% of suspended solids. The moisture content of sludge is 98%. If the sludge is reduced to half of its volume, then the moisture content of the reduced volume sludge is –a)92%b)95%c)94%d)96%Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A sedimentation tank is treating 2 MLD of sewage per day containing 225 mg/L of suspended solids. The tank removes 30% of suspended solids. The moisture content of sludge is 98%. If the sludge is reduced to half of its volume, then the moisture content of the reduced volume sludge is –a)92%b)95%c)94%d)96%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sedimentation tank is treating 2 MLD of sewage per day containing 225 mg/L of suspended solids. The tank removes 30% of suspended solids. The moisture content of sludge is 98%. If the sludge is reduced to half of its volume, then the moisture content of the reduced volume sludge is –a)92%b)95%c)94%d)96%Correct answer is option 'D'. Can you explain this answer?.
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