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A sedimentation tank is treating 4 million litres of sewage per day containing 200 ppm of
suspended solids. The tank removes 50% of suspended solids. Calculate the quantity of wet
sludge produced per day if moisture content of sludge is 98%. Assume unit weight of wet
sludge is 1000 kg/m3.?
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A sedimentation tank is treating 4 million litres of sewage per day co...
Quantity of Wet Sludge Produced per Day

Given data:
- Sewage flow rate: 4 million litres per day
- Suspended solids concentration: 200 ppm
- Removal efficiency of suspended solids: 50%
- Moisture content of sludge: 98%
- Unit weight of wet sludge: 1000 kg/m3

Step 1: Calculation of Suspended Solids Removed
To determine the quantity of suspended solids removed, we need to calculate the total suspended solids (TSS) in the influent and effluent of the sedimentation tank.

Influent TSS = Sewage flow rate * Suspended solids concentration
= 4 million litres/day * 200 ppm
= 800 kg/day

Effluent TSS = Influent TSS * (1 - Removal efficiency)
= 800 kg/day * (1 - 0.50)
= 400 kg/day

Step 2: Calculation of Wet Sludge Produced
The wet sludge produced can be calculated by subtracting the TSS in the effluent from the TSS in the influent.

Wet sludge produced = Influent TSS - Effluent TSS
= 800 kg/day - 400 kg/day
= 400 kg/day

Step 3: Calculation of Dry Sludge Produced
To calculate the dry sludge produced, we need to determine the dry solids content in the wet sludge.

Dry solids content = 100% - Moisture content
= 100% - 98%
= 2%

Dry sludge produced = Wet sludge produced * (Dry solids content / 100)
= 400 kg/day * (2 / 100)
= 8 kg/day

Therefore, the quantity of wet sludge produced per day is 400 kg/day, and the quantity of dry sludge produced per day is 8 kg/day.
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A sedimentation tank is treating 4 million litres of sewage per day containing 200 ppm ofsuspended solids. The tank removes 50% of suspended solids. Calculate the quantity of wetsludge produced per day if moisture content of sludge is 98%. Assume unit weight of wetsludge is 1000 kg/m3.?
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A sedimentation tank is treating 4 million litres of sewage per day containing 200 ppm ofsuspended solids. The tank removes 50% of suspended solids. Calculate the quantity of wetsludge produced per day if moisture content of sludge is 98%. Assume unit weight of wetsludge is 1000 kg/m3.? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A sedimentation tank is treating 4 million litres of sewage per day containing 200 ppm ofsuspended solids. The tank removes 50% of suspended solids. Calculate the quantity of wetsludge produced per day if moisture content of sludge is 98%. Assume unit weight of wetsludge is 1000 kg/m3.? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sedimentation tank is treating 4 million litres of sewage per day containing 200 ppm ofsuspended solids. The tank removes 50% of suspended solids. Calculate the quantity of wetsludge produced per day if moisture content of sludge is 98%. Assume unit weight of wetsludge is 1000 kg/m3.?.
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