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An aeration basin with a volume of 400 m³ contains mixed liquor with suspended solid concentration of 1000 mg/l. The amount of mixed liquor suspended solids in the tank is (a) 500 kg (b) 250 kg (d) 400 kg Correct option is 'd'. Can any one explain?
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An aeration basin with a volume of 400 m³ contains mixed liquor with s...
Problem:
An aeration basin with a volume of 400 m³ contains mixed liquor with a suspended solid concentration of 1000 mg/l. The amount of mixed liquor suspended solids in the tank is:
(a) 500 kg
(b) 250 kg
(d) 400 kg

Solution:
To find the amount of mixed liquor suspended solids in the tank, we need to calculate the total mass of the suspended solids. We can do this by multiplying the volume of the tank with the suspended solid concentration.

Step 1: Calculate the total mass of suspended solids.
Given:
- Volume of the tank (V) = 400 m³
- Suspended solid concentration (C) = 1000 mg/l

The suspended solid concentration is given in milligrams per liter (mg/l). To convert it to kilograms, we need to divide by 1000.
So, the suspended solid concentration in kilograms per liter (kg/l) is:
C = 1000 mg/l / 1000 = 1 kg/l

The total mass of suspended solids in the tank is given by the product of the volume and the concentration:
Total mass of suspended solids = Volume × Concentration
= 400 m³ × 1 kg/l
= 400 kg

Therefore, the correct option is (d) 400 kg.
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An aeration basin with a volume of 400 m³ contains mixed liquor with suspended solid concentration of 1000 mg/l. The amount of mixed liquor suspended solids in the tank is (a) 500 kg (b) 250 kg (d) 400 kg Correct option is 'd'. Can any one explain?
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