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A sewage treatment plant receives sewage at a flow rate of 5000 m3/day. The total suspended solids (TSS) concentration in the sewage at the inlet of primary clarifier is 200 mg/L. After the primary treatment, the TSS concentration in sewage is reduced by 60 %. The sludge from the primary clarifier contains 2 % solids concentration. Subsequently, the sludge is subjected to gravity thickening process to achieve a solids concentration of 6%. Assume that the density of sludge, before and after thickening, is 1000 kg/m3.
The daily volume of the thickened sludge (in m3 /day) will be_________. (round off to the nearest integer)
    Correct answer is '10'. Can you explain this answer?
    Most Upvoted Answer
    A sewage treatment plant receives sewage at a flow rate of 5000 m3/day...
    Calculation of Daily TSS Load

    - Daily flow rate = 5000 m3/day
    - Inlet TSS concentration = 200 mg/L
    - Daily TSS load = Daily flow rate x TSS concentration = 5000 x 200/1000 = 1000 kg/day

    Calculation of TSS Concentration after Primary Treatment

    - TSS concentration reduction after primary treatment = 60%
    - TSS concentration after primary treatment = Inlet TSS concentration x (100% - reduction %) = 200 x (100% - 60%) = 80 mg/L

    Calculation of Sludge Volume after Primary Clarifier

    - Sludge production rate = 2% of the daily flow rate = 0.02 x 5000 = 100 m3/day
    - Sludge solids concentration = 2%
    - Sludge mass = Sludge volume x Sludge density x Sludge solids concentration
    - Mass of sludge produced per day = 100 x 1000 x 0.02 = 2000 kg/day
    - Sludge volume after primary clarifier = Sludge mass / Sludge density = 2000 / 1000 = 2 m3/day

    Calculation of Sludge Volume after Gravity Thickening

    - Solids concentration after gravity thickening = 6%
    - Density of thickened sludge = 1000 kg/m3
    - Mass of thickened sludge = Sludge volume x Sludge density x Solids concentration
    - Mass of thickened sludge per day = 2 x 1000 x 0.06 = 120 kg/day
    - Sludge volume after thickening = Sludge mass / Sludge density = 120 / 1000 = 0.12 m3/day

    Rounding off to the nearest integer, the daily volume of the thickened sludge is 10 m3/day.
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    Community Answer
    A sewage treatment plant receives sewage at a flow rate of 5000 m3/day...

    Solid content in thickener

    i.e., 6% of total mass of sludge
    ∴ Total mass of sludge 

    ∴ Volume of sludge  
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    A sewage treatment plant receives sewage at a flow rate of 5000 m3/day. The total suspended solids (TSS) concentration in the sewage at the inlet of primary clarifier is 200 mg/L. After the primary treatment, the TSS concentration in sewage is reduced by 60 %. The sludge from the primary clarifier contains 2 % solids concentration. Subsequently, the sludge is subjected to gravity thickening process to achieve a solids concentration of 6%. Assume that the density of sludge, before and after thickening, is 1000 kg/m3.The daily volume of the thickened sludge (in m3 /day) will be_________. (round off to the nearest integer)Correct answer is '10'. Can you explain this answer?
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    A sewage treatment plant receives sewage at a flow rate of 5000 m3/day. The total suspended solids (TSS) concentration in the sewage at the inlet of primary clarifier is 200 mg/L. After the primary treatment, the TSS concentration in sewage is reduced by 60 %. The sludge from the primary clarifier contains 2 % solids concentration. Subsequently, the sludge is subjected to gravity thickening process to achieve a solids concentration of 6%. Assume that the density of sludge, before and after thickening, is 1000 kg/m3.The daily volume of the thickened sludge (in m3 /day) will be_________. (round off to the nearest integer)Correct answer is '10'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A sewage treatment plant receives sewage at a flow rate of 5000 m3/day. The total suspended solids (TSS) concentration in the sewage at the inlet of primary clarifier is 200 mg/L. After the primary treatment, the TSS concentration in sewage is reduced by 60 %. The sludge from the primary clarifier contains 2 % solids concentration. Subsequently, the sludge is subjected to gravity thickening process to achieve a solids concentration of 6%. Assume that the density of sludge, before and after thickening, is 1000 kg/m3.The daily volume of the thickened sludge (in m3 /day) will be_________. (round off to the nearest integer)Correct answer is '10'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sewage treatment plant receives sewage at a flow rate of 5000 m3/day. The total suspended solids (TSS) concentration in the sewage at the inlet of primary clarifier is 200 mg/L. After the primary treatment, the TSS concentration in sewage is reduced by 60 %. The sludge from the primary clarifier contains 2 % solids concentration. Subsequently, the sludge is subjected to gravity thickening process to achieve a solids concentration of 6%. Assume that the density of sludge, before and after thickening, is 1000 kg/m3.The daily volume of the thickened sludge (in m3 /day) will be_________. (round off to the nearest integer)Correct answer is '10'. Can you explain this answer?.
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