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A secondary clarifier handles a total flow of 9600 m3 /d from a the aeration tank of a conventional activated-sludge treatment system. The concentration of solids in the flow from the aeration tank is 3000 mg/L. The clarifier is required to thicken the solids to 12000 mg/L and hence it is to be designed for a solid flux of 3.2 kg/m2 × h . The surface area of the designed clarifier for thickening (in m2, in integer) is_________
Correct answer is '375'. Can you explain this answer?
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A secondary clarifier handles a total flow of 9600 m3 /d from a the ae...
Q = 9600 m3 /day
X = 3000 mg/L
Xu = 12000 mg/L
Surface area required
X = 3000 mg/L
Xu = 12000 mg/L
Surface area required
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A secondary clarifier handles a total flow of 9600 m3 /d from a the ae...
To design the secondary clarifier, we need to calculate the required area.
The solid flux is given as 3.2 kg/m^2. This means that for every square meter of the clarifier surface, 3.2 kg of solids should be collected per day.
We know that the total flow is 9600 m^3/d. To calculate the required area, we need to convert this flow rate to a surface area using the solid flux.
First, let's convert the flow rate from m^3/d to L/d:
9600 m^3/d = 9600 * 1000 L/d = 9,600,000 L/d
Next, let's calculate the mass of solids in the flow from the aeration tank:
Mass of solids = flow rate * concentration
Mass of solids = 9,600,000 L/d * 3000 mg/L = 28,800,000,000 mg/d
Now, let's calculate the required area:
Area = mass of solids / solid flux
Area = 28,800,000,000 mg/d / 3.2 kg/m^2 = 9,000,000,000 mg/m^2 / 3.2 kg/m^2 = 2,812,500,000 m^2
Therefore, the secondary clarifier should be designed with an area of approximately 2,812,500,000 m^2 to achieve a solid flux of 3.2 kg/m^2.
The solid flux is given as 3.2 kg/m^2. This means that for every square meter of the clarifier surface, 3.2 kg of solids should be collected per day.
We know that the total flow is 9600 m^3/d. To calculate the required area, we need to convert this flow rate to a surface area using the solid flux.
First, let's convert the flow rate from m^3/d to L/d:
9600 m^3/d = 9600 * 1000 L/d = 9,600,000 L/d
Next, let's calculate the mass of solids in the flow from the aeration tank:
Mass of solids = flow rate * concentration
Mass of solids = 9,600,000 L/d * 3000 mg/L = 28,800,000,000 mg/d
Now, let's calculate the required area:
Area = mass of solids / solid flux
Area = 28,800,000,000 mg/d / 3.2 kg/m^2 = 9,000,000,000 mg/m^2 / 3.2 kg/m^2 = 2,812,500,000 m^2
Therefore, the secondary clarifier should be designed with an area of approximately 2,812,500,000 m^2 to achieve a solid flux of 3.2 kg/m^2.
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A secondary clarifier handles a total flow of 9600 m3 /d from a the aeration tank of a conventional activated-sludge treatment system. The concentration of solids in the flow from the aeration tank is 3000 mg/L. The clarifier is required to thicken the solids to 12000 mg/L and hence it is to be designed for a solid flux of 3.2 kg/m2 × h . The surface area of the designed clarifier for thickening (in m2, in integer) is_________Correct answer is '375'. Can you explain this answer?
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A secondary clarifier handles a total flow of 9600 m3 /d from a the aeration tank of a conventional activated-sludge treatment system. The concentration of solids in the flow from the aeration tank is 3000 mg/L. The clarifier is required to thicken the solids to 12000 mg/L and hence it is to be designed for a solid flux of 3.2 kg/m2 × h . The surface area of the designed clarifier for thickening (in m2, in integer) is_________Correct answer is '375'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A secondary clarifier handles a total flow of 9600 m3 /d from a the aeration tank of a conventional activated-sludge treatment system. The concentration of solids in the flow from the aeration tank is 3000 mg/L. The clarifier is required to thicken the solids to 12000 mg/L and hence it is to be designed for a solid flux of 3.2 kg/m2 × h . The surface area of the designed clarifier for thickening (in m2, in integer) is_________Correct answer is '375'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A secondary clarifier handles a total flow of 9600 m3 /d from a the aeration tank of a conventional activated-sludge treatment system. The concentration of solids in the flow from the aeration tank is 3000 mg/L. The clarifier is required to thicken the solids to 12000 mg/L and hence it is to be designed for a solid flux of 3.2 kg/m2 × h . The surface area of the designed clarifier for thickening (in m2, in integer) is_________Correct answer is '375'. Can you explain this answer?.
A secondary clarifier handles a total flow of 9600 m3 /d from a the aeration tank of a conventional activated-sludge treatment system. The concentration of solids in the flow from the aeration tank is 3000 mg/L. The clarifier is required to thicken the solids to 12000 mg/L and hence it is to be designed for a solid flux of 3.2 kg/m2 × h . The surface area of the designed clarifier for thickening (in m2, in integer) is_________Correct answer is '375'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A secondary clarifier handles a total flow of 9600 m3 /d from a the aeration tank of a conventional activated-sludge treatment system. The concentration of solids in the flow from the aeration tank is 3000 mg/L. The clarifier is required to thicken the solids to 12000 mg/L and hence it is to be designed for a solid flux of 3.2 kg/m2 × h . The surface area of the designed clarifier for thickening (in m2, in integer) is_________Correct answer is '375'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A secondary clarifier handles a total flow of 9600 m3 /d from a the aeration tank of a conventional activated-sludge treatment system. The concentration of solids in the flow from the aeration tank is 3000 mg/L. The clarifier is required to thicken the solids to 12000 mg/L and hence it is to be designed for a solid flux of 3.2 kg/m2 × h . The surface area of the designed clarifier for thickening (in m2, in integer) is_________Correct answer is '375'. Can you explain this answer?.
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