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A piece of copper and another of germanium are cooled from room temperature to 77K, the resistance of
  • a)
    copper increases and germanium decreases
  • b)
    each of them decreases 
  • c)
    each of them increases
  • d)
    copper decreases and germanium increases
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A piece of copper and another of germanium are cooled from room temper...
Copper is a conductor, so its resistance decreases on decreasing temperature as thermal agitation decreases,; whereas germanium is semiconductor therefore  on decreasing temperature resistance increases.
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A piece of copper and another of germanium are cooled from room temperature to 77K, the resistance ofa)copper increases and germanium decreasesb)each of them decreasesc)each of them increasesd)copper decreases and germanium increasesCorrect answer is option 'D'. Can you explain this answer?
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A piece of copper and another of germanium are cooled from room temperature to 77K, the resistance ofa)copper increases and germanium decreasesb)each of them decreasesc)each of them increasesd)copper decreases and germanium increasesCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A piece of copper and another of germanium are cooled from room temperature to 77K, the resistance ofa)copper increases and germanium decreasesb)each of them decreasesc)each of them increasesd)copper decreases and germanium increasesCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A piece of copper and another of germanium are cooled from room temperature to 77K, the resistance ofa)copper increases and germanium decreasesb)each of them decreasesc)each of them increasesd)copper decreases and germanium increasesCorrect answer is option 'D'. Can you explain this answer?.
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