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What would be the concentration of returned sludge (in mg/l) if the sludge volume index for an activated sludge is 92 ml per gm
Correct answer is between '10869,10870'. Can you explain this answer?
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What would be the concentration of returned sludge (in mg/l) if the sl...
Concentration of returned sludge =
= 10869.56 mg/l
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What would be the concentration of returned sludge (in mg/l) if the sl...
Calculation of Returned Sludge Concentration
Sludge Volume Index (SVI) is the measure of the settling properties of activated sludge. The formula to calculate SVI is given as:
SVI = (Volume of sludge, in ml) / (Weight of dry solids, in gm)
Given that the SVI for activated sludge is 92 ml per gm, we can calculate the weight of dry solids as:
Weight of dry solids = Volume of sludge / SVI
Now, let's assume that the volume of sludge is 1000 ml. Then,
Weight of dry solids = 1000 ml / 92 ml per gm = 10.8696 gm
Since the concentration of sludge is usually expressed in mg/l, we need to convert the weight of dry solids from gm to mg and the volume of sludge from ml to l.
Weight of dry solids = 10.8696 gm = 10,869.6 mg
Volume of sludge = 1000 ml = 1 l
Therefore, the concentration of returned sludge in mg/l is:
Concentration = Weight of dry solids / Volume of sludge
Concentration = 10,869.6 mg / 1 l = 10,869.6 mg/l
Therefore, the concentration of returned sludge is between 10,869 and 10,870 mg/l.
Sludge Volume Index (SVI) is the measure of the settling properties of activated sludge. The formula to calculate SVI is given as:
SVI = (Volume of sludge, in ml) / (Weight of dry solids, in gm)
Given that the SVI for activated sludge is 92 ml per gm, we can calculate the weight of dry solids as:
Weight of dry solids = Volume of sludge / SVI
Now, let's assume that the volume of sludge is 1000 ml. Then,
Weight of dry solids = 1000 ml / 92 ml per gm = 10.8696 gm
Since the concentration of sludge is usually expressed in mg/l, we need to convert the weight of dry solids from gm to mg and the volume of sludge from ml to l.
Weight of dry solids = 10.8696 gm = 10,869.6 mg
Volume of sludge = 1000 ml = 1 l
Therefore, the concentration of returned sludge in mg/l is:
Concentration = Weight of dry solids / Volume of sludge
Concentration = 10,869.6 mg / 1 l = 10,869.6 mg/l
Therefore, the concentration of returned sludge is between 10,869 and 10,870 mg/l.
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What would be the concentration of returned sludge (in mg/l) if the sludge volume index for an activated sludge is 92 ml per gmCorrect answer is between '10869,10870'. Can you explain this answer?
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