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Deoxygenation constant [kD] at 40o C ----- per day. Assume kD at 20o C is 0.13 per day.
    Correct answer is between '0.32,0.34'. Can you explain this answer?
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    Deoxygenation constant [kD] at 40oC ----- per day. Assume kDat 20oC is...
    [kD]To= [kD]20o[1.047]T - 20               
    [kD]40oC = 0.13 [1.047]40 - 20               
    [kD]40oC = 0.13 [1.047]20               
    [kD]40oC = 0.326 per day
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    Deoxygenation constant [kD] at 40oC ----- per day. Assume kDat 20oC is 0.13 per day.Correct answer is between '0.32,0.34'. Can you explain this answer?
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    Deoxygenation constant [kD] at 40oC ----- per day. Assume kDat 20oC is 0.13 per day.Correct answer is between '0.32,0.34'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Deoxygenation constant [kD] at 40oC ----- per day. Assume kDat 20oC is 0.13 per day.Correct answer is between '0.32,0.34'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Deoxygenation constant [kD] at 40oC ----- per day. Assume kDat 20oC is 0.13 per day.Correct answer is between '0.32,0.34'. Can you explain this answer?.
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