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Consider the following proposition:
(p→q)∧(q→r)→(p→r)∨(r→p) 
Above proposition is a
  • a)
    Contradiction 
  • b)
    Tautology
  • c)
    Contingency
  • d)
    None of the above
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Consider the following proposition:(p→q)∧(q→r)→(p&r...
≡ 1
Hence it is a tautology.
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Consider the following proposition:(p→q)∧(q→r)→(p→r)∨(r→p)Above proposition is aa)Contradictionb)Tautologyc)Contingencyd)None of the aboveCorrect answer is option 'B'. Can you explain this answer?
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