A 3 uf capacitor is charged to 300 v. And a 2uf capacitor is charged to 200 v. Tha capacitors are then connected in parallel with plates of opposite polarity joined together. What amount of charge will flow, when the plates are so connected?

Question

Answer

Calculation of Charge Flow in Capacitors Connected in Parallel

Step 1: Calculation of Total Capacitance

When two capacitors are connected in parallel, the total capacitance is given as:
C = C1 + C2
C = 3uf + 2uf = 5uf

Step 2: Calculation of Total Charge

The total charge stored in each capacitor is given by:
Q = CV
Q1 = 3uf * 300v = 900uC
Q2 = 2uf * 200v = 400uC

The total charge stored in the capacitors is given as:
Q = Q1 + Q2
Q = 900uC + 400uC = 1300uC

Step 3: Calculation of Charge Flow

When the plates of the capacitors are connected in parallel, they act as a single capacitor with capacitance C = 5uf. The voltage across the capacitors is the same and equal to V = 300v.

The total charge stored in the capacitor connected in parallel is given by:
Q = CV
Q = 5uf * 300v = 1500uC

The charge flow is given by the difference in charge before and after the connection.
Charge flow = Q - (Q1 + Q2)
Charge flow = 1500uC - 1300uC
Charge flow = 200uC

Therefore, the charge flow when the plates are connected is 200uC.

Answer

The charge will flow till their final potential will became same and u can use cv_ cv /c +c so final potential so find everything

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