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The Maximum velocity through a circular channel takes place when the depth of flow is equal to:
  • a)
    0.95 times the diameter
  • b)
    0.5 times the diameter
  • c)
    0.81 times the diameter
  • d)
    0.3 times the diameter
Correct answer is option 'C'. Can you explain this answer?
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The Maximum velocity through a circular channel takes place when the d...
Maximum velocity occurs at 0.81 times the diameter and maximum discharge occurs at 0.95 times the diameter.
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The Maximum velocity through a circular channel takes place when the d...
Maximum velocity in circular channels

The maximum velocity through a circular channel occurs at a specific depth of flow. This depth of flow is related to the diameter of the circular channel.

Formula

The velocity of flow in a circular channel can be calculated using the formula:

V = (1/n) * R^(2/3) * S^(1/2)

where V is the velocity of flow, n is the Manning roughness coefficient, R is the hydraulic radius of the channel, and S is the slope of the channel.

Hydraulic radius

The hydraulic radius of a circular channel is given by the formula:

R = D/4

where D is the diameter of the channel.

Depth of flow

The depth of flow in a circular channel can be related to the hydraulic radius using the formula:

y = D/2 - R

where y is the depth of flow.

Maximum velocity

The maximum velocity through a circular channel occurs when the hydraulic radius is at its maximum value. This occurs when the depth of flow is equal to 0.81 times the diameter of the channel.

Therefore, the correct answer is option C: 0.81 times the diameter.
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The Maximum velocity through a circular channel takes place when the depth of flow is equal to:a)0.95 times the diameterb)0.5 times the diameterc)0.81 times the diameterd)0.3 times the diameterCorrect answer is option 'C'. Can you explain this answer?
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