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A watershed of area 90 hectare has a runoff coefficient of 0.4. A storm of duration larger than the time of concentration of the watershed and of intensity 4.5 cm/h creates a peak discharge of
- a)11.3 m3/s
- b)0.45 m3/s
- c)450 m3/s
- d)4.5 m3/s
Correct answer is option 'D'. Can you explain this answer?
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A watershed of area 90 hectare has a runoff coefficient of 0.4. A stor...
Peak flood by rational formula is given by QP = 136 KPcA
Where, K = Co-efficient of run off; pc = intensity (cm/hr); A = area in hectare
Where, K = Co-efficient of run off; pc = intensity (cm/hr); A = area in hectare
Most Upvoted Answer
A watershed of area 90 hectare has a runoff coefficient of 0.4. A stor...
Calculation of Peak Discharge in a Watershed
Given data:
Watershed area = 90 hectares
Runoff coefficient = 0.4
Storm intensity = 4.5 cm/h
Step 1: Calculation of Total Rainfall
The total rainfall can be calculated by multiplying the storm intensity with the duration of the storm. As the duration of the storm is not given, we assume it to be equal to the time of concentration of the watershed.
Time of concentration (Tc) is the time taken by the water to travel from the most remote point to the outlet of the watershed. It can be calculated using the following formula:
Tc = 0.8(L)^0.5
Where L is the length of the longest flow path in meters.
Assuming L to be 1000 meters (as it is not given in the question), we get:
Tc = 0.8(1000)^0.5 = 28.28 minutes
Now, the total rainfall can be calculated as:
Total rainfall = Storm intensity x Storm duration
= 4.5 cm/h x 28.28/60 h
= 2.11 cm
Step 2: Calculation of Runoff
The runoff can be calculated by multiplying the total rainfall with the runoff coefficient. Hence,
Runoff = Total rainfall x Runoff coefficient
= 2.11 cm x 0.4
= 0.844 cm
Step 3: Calculation of Peak Discharge
The peak discharge can be calculated using the Rational method, which is given by the following formula:
Qp = (C x I x A)/3600
Where Qp is the peak discharge in m3/s, C is the runoff coefficient, I is the storm intensity in mm/h, and A is the watershed area in hectares.
Converting the storm intensity from cm/h to mm/h, we get:
I = 4.5 cm/h x 10 mm/cm
= 45 mm/h
Substituting the given values in the formula, we get:
Qp = (0.4 x 45 x 90)/3600
= 1.125 m3/s
= 4.05 m3/h
Therefore, the correct answer is option D, 4.5 m3/s (rounded to one decimal place).
Given data:
Watershed area = 90 hectares
Runoff coefficient = 0.4
Storm intensity = 4.5 cm/h
Step 1: Calculation of Total Rainfall
The total rainfall can be calculated by multiplying the storm intensity with the duration of the storm. As the duration of the storm is not given, we assume it to be equal to the time of concentration of the watershed.
Time of concentration (Tc) is the time taken by the water to travel from the most remote point to the outlet of the watershed. It can be calculated using the following formula:
Tc = 0.8(L)^0.5
Where L is the length of the longest flow path in meters.
Assuming L to be 1000 meters (as it is not given in the question), we get:
Tc = 0.8(1000)^0.5 = 28.28 minutes
Now, the total rainfall can be calculated as:
Total rainfall = Storm intensity x Storm duration
= 4.5 cm/h x 28.28/60 h
= 2.11 cm
Step 2: Calculation of Runoff
The runoff can be calculated by multiplying the total rainfall with the runoff coefficient. Hence,
Runoff = Total rainfall x Runoff coefficient
= 2.11 cm x 0.4
= 0.844 cm
Step 3: Calculation of Peak Discharge
The peak discharge can be calculated using the Rational method, which is given by the following formula:
Qp = (C x I x A)/3600
Where Qp is the peak discharge in m3/s, C is the runoff coefficient, I is the storm intensity in mm/h, and A is the watershed area in hectares.
Converting the storm intensity from cm/h to mm/h, we get:
I = 4.5 cm/h x 10 mm/cm
= 45 mm/h
Substituting the given values in the formula, we get:
Qp = (0.4 x 45 x 90)/3600
= 1.125 m3/s
= 4.05 m3/h
Therefore, the correct answer is option D, 4.5 m3/s (rounded to one decimal place).
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Community Answer
A watershed of area 90 hectare has a runoff coefficient of 0.4. A stor...
Q=k.i.A
= 0.4*4.5cm/h*90hectare
=0.4*(4.5*0.01/3600)m/sec*90*10⁴m²
=4.5m³/sec
= 0.4*4.5cm/h*90hectare
=0.4*(4.5*0.01/3600)m/sec*90*10⁴m²
=4.5m³/sec
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A watershed of area 90 hectare has a runoff coefficient of 0.4. A storm of duration larger than the time of concentration of the watershed and of intensity 4.5 cm/h creates a peak discharge ofa)11.3 m3/sb)0.45 m3/sc)450 m3/sd)4.5 m3/sCorrect answer is option 'D'. Can you explain this answer?
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A watershed of area 90 hectare has a runoff coefficient of 0.4. A storm of duration larger than the time of concentration of the watershed and of intensity 4.5 cm/h creates a peak discharge ofa)11.3 m3/sb)0.45 m3/sc)450 m3/sd)4.5 m3/sCorrect answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A watershed of area 90 hectare has a runoff coefficient of 0.4. A storm of duration larger than the time of concentration of the watershed and of intensity 4.5 cm/h creates a peak discharge ofa)11.3 m3/sb)0.45 m3/sc)450 m3/sd)4.5 m3/sCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A watershed of area 90 hectare has a runoff coefficient of 0.4. A storm of duration larger than the time of concentration of the watershed and of intensity 4.5 cm/h creates a peak discharge ofa)11.3 m3/sb)0.45 m3/sc)450 m3/sd)4.5 m3/sCorrect answer is option 'D'. Can you explain this answer?.
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