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A small piston of 3cm diameter is 40cm above the larger piston of 10cm diameter in a hydraulic jack. A force of 80N is applied on small piston, find the load lifted if working fluid is water?
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A small piston of 3cm diameter is 40cm above the larger piston of 10cm...
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A small piston of 3cm diameter is 40cm above the larger piston of 10cm...
Given:
- Diameter of small piston (d1) = 3 cm
- Diameter of large piston (d2) = 10 cm
- Distance between the two pistons (h) = 40 cm
- Force applied on the small piston (F1) = 80 N
- Working fluid is water

To Find:
- Load lifted by the hydraulic jack

Solution:

Step 1: Calculate the areas of the pistons:
- Area of the small piston (A1) = (π/4) x (d1)^2
=> A1 = (π/4) x (3 cm)^2
=> A1 = 7.07 cm²

- Area of the large piston (A2) = (π/4) x (d2)^2
=> A2 = (π/4) x (10 cm)^2
=> A2 = 78.54 cm²

Step 2: Calculate the pressure on the small piston:
- Pressure on the small piston (P1) = Force applied on small piston (F1) / Area of small piston (A1)
=> P1 = 80 N / 7.07 cm²
=> P1 = 11.31 N/cm²

Step 3: Calculate the pressure on the large piston:
- Pressure on the large piston (P2) = Pressure on small piston (P1) x Area of small piston (A1) / Area of large piston (A2)
=> P2 = 11.31 N/cm² x 7.07 cm² / 78.54 cm²
=> P2 = 1.01 N/cm²

Step 4: Calculate the force on the large piston:
- Force on the large piston (F2) = Pressure on large piston (P2) x Area of large piston (A2)
=> F2 = 1.01 N/cm² x 78.54 cm²
=> F2 = 79.99 N

Step 5: Calculate the load lifted:
- The load lifted is equal to the force on the large piston (F2)
=> Load lifted = 79.99 N

Explanation:
- The hydraulic jack works on the principle of Pascal's law, which states that when pressure is applied to a fluid in a confined space, it is transmitted equally in all directions.
- In this case, when a force (F1) is applied to the small piston, it creates a pressure (P1) on the fluid in the system. This pressure is transmitted equally to the larger piston.
- The pressure on the large piston (P2) is calculated using the ratio of the areas of the pistons. This pressure then creates a force (F2) on the large piston, which is equal to the load lifted.
- By using the given values and formulas, we can calculate the load lifted to be 79.99 N.
- It is important to note that the working fluid being water affects the density and properties of the fluid, but it does not significantly impact the calculations in this case.
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A small piston of 3cm diameter is 40cm above the larger piston of 10cm diameter in a hydraulic jack. A force of 80N is applied on small piston, find the load lifted if working fluid is water?
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A small piston of 3cm diameter is 40cm above the larger piston of 10cm diameter in a hydraulic jack. A force of 80N is applied on small piston, find the load lifted if working fluid is water? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A small piston of 3cm diameter is 40cm above the larger piston of 10cm diameter in a hydraulic jack. A force of 80N is applied on small piston, find the load lifted if working fluid is water? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A small piston of 3cm diameter is 40cm above the larger piston of 10cm diameter in a hydraulic jack. A force of 80N is applied on small piston, find the load lifted if working fluid is water?.
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