JEE Exam > JEE Questions > One mole of He ions is excited. Spectral ana...
Start Learning for Free
One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.?
Most Upvoted Answer
One mole of He ions is excited. Spectral analysis showed the existenc...
**Calculating the Total Energy Evolved when all He+ ions return to the ground state**
Given information:
- 1 mole of He+ ions is excited.
- Spectral analysis showed 50% of the ions are in the 3rd level, 25% in the 2nd level, and the remaining 25% in the ground state.
- The ionization energy of He is 54.4 eV.
To calculate the total energy evolved when all the He+ ions return to the ground state, we need to consider the energy levels and their respective energies.
**Energy Levels and Energies:**
- Ground state (n = 1): E1
- 2nd level (n = 2): E2
- 3rd level (n = 3): E3
**Calculating the Energy Difference between Levels:**
The energy difference between levels can be calculated using the formula:
ΔE = |Ef - Ei|
Where ΔE is the energy difference, Ef is the final energy level, and Ei is the initial energy level.
- ΔE1-2 = |E2 - E1|
- ΔE2-3 = |E3 - E2|
- ΔE3-1 = |E1 - E3|
**Calculating the Energy Evolved for each Transition:**
The energy evolved for each transition is given by the equation:
Energy evolved = Percent in initial state * Number of ions * ΔE
- Energy evolved 1-2 = 25% * (1 mole) * ΔE1-2
- Energy evolved 2-3 = 50% * (1 mole) * ΔE2-3
- Energy evolved 3-1 = 25% * (1 mole) * ΔE3-1
**Calculating the Total Energy Evolved:**
The total energy evolved is the sum of the energies evolved for each transition.
Total energy evolved = Energy evolved 1-2 + Energy evolved 2-3 + Energy evolved 3-1
Substituting the calculated values in the equation, we can find the total energy evolved.
Remember to convert the energy difference from electron volts (eV) to joules (J) if necessary, using the conversion factor 1 eV = 1.6 x 10^-19 J.
Note: The specific values for the energy levels (E1, E2, and E3) are not provided in the question. You may need to refer to a periodic table or atomic data to obtain the accurate energy values.
Given information:
- 1 mole of He+ ions is excited.
- Spectral analysis showed 50% of the ions are in the 3rd level, 25% in the 2nd level, and the remaining 25% in the ground state.
- The ionization energy of He is 54.4 eV.
To calculate the total energy evolved when all the He+ ions return to the ground state, we need to consider the energy levels and their respective energies.
**Energy Levels and Energies:**
- Ground state (n = 1): E1
- 2nd level (n = 2): E2
- 3rd level (n = 3): E3
**Calculating the Energy Difference between Levels:**
The energy difference between levels can be calculated using the formula:
ΔE = |Ef - Ei|
Where ΔE is the energy difference, Ef is the final energy level, and Ei is the initial energy level.
- ΔE1-2 = |E2 - E1|
- ΔE2-3 = |E3 - E2|
- ΔE3-1 = |E1 - E3|
**Calculating the Energy Evolved for each Transition:**
The energy evolved for each transition is given by the equation:
Energy evolved = Percent in initial state * Number of ions * ΔE
- Energy evolved 1-2 = 25% * (1 mole) * ΔE1-2
- Energy evolved 2-3 = 50% * (1 mole) * ΔE2-3
- Energy evolved 3-1 = 25% * (1 mole) * ΔE3-1
**Calculating the Total Energy Evolved:**
The total energy evolved is the sum of the energies evolved for each transition.
Total energy evolved = Energy evolved 1-2 + Energy evolved 2-3 + Energy evolved 3-1
Substituting the calculated values in the equation, we can find the total energy evolved.
Remember to convert the energy difference from electron volts (eV) to joules (J) if necessary, using the conversion factor 1 eV = 1.6 x 10^-19 J.
Note: The specific values for the energy levels (E1, E2, and E3) are not provided in the question. You may need to refer to a periodic table or atomic data to obtain the accurate energy values.
Community Answer
One mole of He ions is excited. Spectral analysis showed the existenc...
Ans is 2× 10^25 eV.
can't upload image due to upload restriction.
can't upload image due to upload restriction.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
Question Description
One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.?.
One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.?.
Solutions for One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.? defined & explained in the simplest way possible. Besides giving the explanation of
One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.?, a detailed solution for One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.? has been provided alongside types of One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.? theory, EduRev gives you an
ample number of questions to practice One mole of He ions is excited. Spectral analysis showed the existence of 50% ions 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionisation energy of He is 54.4 eV. Calculate the total energy evolved when all the ions return to the ground state.? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup on EduRev and stay on top of your study goals
10M+ students crushing their study goals daily