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In the figure, not drawn to scale, ACDF is a rectangle and BDE is a triangle. Find ∠BED 
  • a)
    42o                    
  • b)
    52o              
  • c)
    128         
  • d)
    134o  
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In the figure, not drawn to scale, ACDF is a rectangle and BDE is a tr...
∠CDB+∠BDE = 90 
(Angle of a rectangle) 
⇒ 48o+∠BDE = 90o 
⇒ ∠BDE = 90o−48= 42o 
In ΔBED ∠EBD+∠BDE+∠BED = 180o  
(Angle sum property) 
⇒ 86o+42o+∠BED = 180
⇒ ∠BED = 180o−(86o+42o) = 52o
This question is part of UPSC exam. View all Class 7 courses
Most Upvoted Answer
In the figure, not drawn to scale, ACDF is a rectangle and BDE is a tr...
Picture is not clear..... sorry can't answer
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In the figure, not drawn to scale, ACDF is a rectangle and BDE is a triangle. Find∠BEDa)42o b)52oc)128od)134oCorrect answer is option 'B'. Can you explain this answer?
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