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A channel-type grit chamber has a flow-through velocity of 0.15 m/s, a depth of 0.8 m and a length of 10 m. For inorganic particles with the specific gravity of 2.7, and considering kinematic viscosity of 8×10-7 m2/s the largest diameter that can be removed with 95% efficiency is
- a)0.0452 mm
- b)0.0786 mm
- c)0.0873 mm
- d)0.0992 mm
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A channel-type grit chamber has a flow-through velocity of 0.15 m/s, a...
The settling velocity can be determined through the equation,
where H = depth of the tank, L = length of the tank, Vs = Settling velocity, and VH = Flow through velocity
Now, using Stokes law,
where H = depth of the tank, L = length of the tank, Vs = Settling velocity, and VH = Flow through velocity
Now, using Stokes law,
where G = specific gravity of the particle, ν =kinematic viscosity of the particle, g = acceleration due to gravity, d = diameter of the particle
For 95% removal efficiency,
d = 9.92 × 10−5m
d = 0.0992.mm
d = 9.92 × 10−5m
d = 0.0992.mm
Most Upvoted Answer
A channel-type grit chamber has a flow-through velocity of 0.15 m/s, a...
To calculate the settling velocity of inorganic particles in the grit chamber, we can use Stoke's Law, which states that the settling velocity (Vs) of a particle in a fluid is given by:
Vs = (2/9) * ((ρp - ρf) / η) * g * r^2
Where:
- Vs is the settling velocity of the particle (m/s)
- ρp is the density of the particle (kg/m^3)
- ρf is the density of the fluid (kg/m^3)
- η is the kinematic viscosity of the fluid (m^2/s)
- g is the acceleration due to gravity (9.81 m/s^2)
- r is the radius of the particle (m)
Since we are given the specific gravity of the particle (SGp = ρp / ρw), we can calculate its density as follows:
ρp = SGp * ρw
Where:
- SGp is the specific gravity of the particle (dimensionless)
- ρw is the density of water (1000 kg/m^3 at room temperature)
Given data:
- Specific gravity of the particle (SGp) = 2.7
- Kinematic viscosity (η) = 8 x 10^-6 m^2/s
- Depth of the grit chamber (H) = 0.8 m
To calculate the radius of the particle, we need to know its diameter. Let's assume a particle diameter of 0.1 mm (0.0001 m).
Using the given data and assumptions, we can now calculate the settling velocity:
1. Calculate the density of the particle:
ρw = 1000 kg/m^3 (density of water)
ρp = SGp * ρw = 2.7 * 1000 kg/m^3 = 2700 kg/m^3
2. Calculate the radius of the particle:
r = diameter / 2 = 0.0001 m / 2 = 0.00005 m
3. Calculate the settling velocity:
Vs = (2/9) * ((ρp - ρf) / η) * g * r^2
Vs = (2/9) * ((2700 - 1000) / 8 x 10^-6) * 9.81 * (0.00005)^2
Vs ≈ 0.000126 m/s
Therefore, the settling velocity of inorganic particles in the grit chamber is approximately 0.000126 m/s.
Vs = (2/9) * ((ρp - ρf) / η) * g * r^2
Where:
- Vs is the settling velocity of the particle (m/s)
- ρp is the density of the particle (kg/m^3)
- ρf is the density of the fluid (kg/m^3)
- η is the kinematic viscosity of the fluid (m^2/s)
- g is the acceleration due to gravity (9.81 m/s^2)
- r is the radius of the particle (m)
Since we are given the specific gravity of the particle (SGp = ρp / ρw), we can calculate its density as follows:
ρp = SGp * ρw
Where:
- SGp is the specific gravity of the particle (dimensionless)
- ρw is the density of water (1000 kg/m^3 at room temperature)
Given data:
- Specific gravity of the particle (SGp) = 2.7
- Kinematic viscosity (η) = 8 x 10^-6 m^2/s
- Depth of the grit chamber (H) = 0.8 m
To calculate the radius of the particle, we need to know its diameter. Let's assume a particle diameter of 0.1 mm (0.0001 m).
Using the given data and assumptions, we can now calculate the settling velocity:
1. Calculate the density of the particle:
ρw = 1000 kg/m^3 (density of water)
ρp = SGp * ρw = 2.7 * 1000 kg/m^3 = 2700 kg/m^3
2. Calculate the radius of the particle:
r = diameter / 2 = 0.0001 m / 2 = 0.00005 m
3. Calculate the settling velocity:
Vs = (2/9) * ((ρp - ρf) / η) * g * r^2
Vs = (2/9) * ((2700 - 1000) / 8 x 10^-6) * 9.81 * (0.00005)^2
Vs ≈ 0.000126 m/s
Therefore, the settling velocity of inorganic particles in the grit chamber is approximately 0.000126 m/s.
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A channel-type grit chamber has a flow-through velocity of 0.15 m/s, a depth of 0.8 m and a length of 10 m.For inorganic particles with the specific gravity of 2.7, and considering kinematic viscosity of 8×10-7m2/s the largest diameter that can be removed with 95% efficiency isa)0.0452 mmb)0.0786 mmc)0.0873 mmd)0.0992 mmCorrect answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A channel-type grit chamber has a flow-through velocity of 0.15 m/s, a depth of 0.8 m and a length of 10 m.For inorganic particles with the specific gravity of 2.7, and considering kinematic viscosity of 8×10-7m2/s the largest diameter that can be removed with 95% efficiency isa)0.0452 mmb)0.0786 mmc)0.0873 mmd)0.0992 mmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A channel-type grit chamber has a flow-through velocity of 0.15 m/s, a depth of 0.8 m and a length of 10 m.For inorganic particles with the specific gravity of 2.7, and considering kinematic viscosity of 8×10-7m2/s the largest diameter that can be removed with 95% efficiency isa)0.0452 mmb)0.0786 mmc)0.0873 mmd)0.0992 mmCorrect answer is option 'D'. Can you explain this answer?.
A channel-type grit chamber has a flow-through velocity of 0.15 m/s, a depth of 0.8 m and a length of 10 m.For inorganic particles with the specific gravity of 2.7, and considering kinematic viscosity of 8×10-7m2/s the largest diameter that can be removed with 95% efficiency isa)0.0452 mmb)0.0786 mmc)0.0873 mmd)0.0992 mmCorrect answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A channel-type grit chamber has a flow-through velocity of 0.15 m/s, a depth of 0.8 m and a length of 10 m.For inorganic particles with the specific gravity of 2.7, and considering kinematic viscosity of 8×10-7m2/s the largest diameter that can be removed with 95% efficiency isa)0.0452 mmb)0.0786 mmc)0.0873 mmd)0.0992 mmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A channel-type grit chamber has a flow-through velocity of 0.15 m/s, a depth of 0.8 m and a length of 10 m.For inorganic particles with the specific gravity of 2.7, and considering kinematic viscosity of 8×10-7m2/s the largest diameter that can be removed with 95% efficiency isa)0.0452 mmb)0.0786 mmc)0.0873 mmd)0.0992 mmCorrect answer is option 'D'. Can you explain this answer?.
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