Two forces of 10n and 6n act on a body .the direction of the forces ar...
Solution:
To find the resultant force on the body, we need to use vector addition. We can apply the Pythagorean theorem to find the magnitude of the resultant force and the inverse tangent function to find the direction of the force.
Step 1: Find the magnitude of the resultant force using Pythagorean theorem.
Let F1 = 10 N and F2 = 6 N be the two forces acting on the body. Then, the magnitude of the resultant force F can be found as follows:
F = √(F1² + F2²)
= √(10² + 6²)
= √136
= 11.66 N (approx.)
Therefore, the magnitude of the resultant force is 11.66 N (approx.).
Step 2: Find the direction of the resultant force using inverse tangent function.
Let θ be the angle between the resultant force and the horizontal axis. Then, we can use the inverse tangent function to find θ as follows:
θ = tan⁻¹(F2/F1)
= tan⁻¹(6/10)
= 31.80° (approx.)
Therefore, the direction of the resultant force is 31.80° (approx.) with respect to the horizontal axis.
Step 3: Final answer
The resultant force on the body is 11.66 N (approx.) in the direction of 31.80° (approx.) with respect to the horizontal axis.
Note: Theta is considered as it is the angle between the resultant force and one of the forces. We can use any of the two forces to find the angle, but we need to make sure that we use the same force to find the components of the forces.
Two forces of 10n and 6n act on a body .the direction of the forces ar...
Jst find max and min force as minimum force is 4 when both in opposite directions so answer is d so easy do more practice if. u r preparing for competition and u r in 12