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The present age of A is twice that of B. 30  years from now, age of A will be 11/2 times that of B. Find the present ages (in years) of A and B respectively.
  • a)
    60,30
  • b)
    30,60
  • c)
    40,50
  • d)
    50,40
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The present age of A is twice that of B. 30 years from now, age of A w...
Let the present ages of A and B be 2x years and x years.
After 30 years, their ages will be
A = (2x+30) years 
B = (x+30)  years So, 2x+30

Present age of B = 30 years ⇒  Present age of  A = 2×30 = 60  years
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Most Upvoted Answer
The present age of A is twice that of B. 30 years from now, age of A w...
Let's assume the present age of B is x years.
According to the given information, the present age of A is twice that of B. Therefore, the present age of A is 2x years.

30 years from now, the age of A will be 11/2 times that of B. So, we can write the equation as:
(2x + 30) = (11/2)(x + 30)

Now, let's solve the equation to find the value of x.

Multiplying both sides of the equation by 2 to eliminate the fraction:
2(2x + 30) = 11(x + 30)
4x + 60 = 11x + 330

Moving the variables to one side and the constants to the other side:
11x - 4x = 330 - 60
7x = 270

Dividing both sides of the equation by 7 to isolate x:
x = 270/7
x = 38.57

Since the age of B cannot be a fraction, we can round it to the nearest whole number. Thus, the present age of B is approximately 39 years.

Now, we can find the present age of A by substituting the value of x into the equation:
A = 2x = 2(39) = 78 years

Therefore, the present age of A is 78 years and the present age of B is 39 years.

Hence, the correct answer is option A: 60,30.
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Community Answer
The present age of A is twice that of B. 30 years from now, age of A w...
B). 30,60
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The present age of A is twice that of B. 30 years from now, age of A will be11/2times that of B. Find the present ages (in years) of A and B respectively.a)60,30b)30,60c)40,50d)50,40Correct answer is option 'A'. Can you explain this answer?
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