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A group consists of equal number of men and women. Of this group 20% of the men and 50% of the women are unemployed. If a person is selected at random from this group, the probability of the selected person being employed is _______.
    Correct answer is '0.65'. Can you explain this answer?
    Verified Answer
    A group consists of equal number of men and women. Of this group 20% o...
    M for men, W for women, E for employed & U for unemployed
    P(M) = 0.5, P(W) = 0.5
    P(U/M) = 0.2 & P(U/W) = 0.5
    ∴ Total probability is
    P(U) = P(M). P(U/M) + P(W) ⋅ P(U/W)
    ⇒ P(U) = 0.35
    ∴ P(E) = 1 – P(U) = 1-0.35 = 0.65
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    A group consists of equal number of men and women. Of this group 20% o...
    Solution:

    Given information:
    - Equal number of men and women in the group.
    - 20% of men are unemployed.
    - 50% of women are unemployed.
    - We need to find the probability of the selected person being employed.

    Step 1: Let's assume that there are 100 people in the group (50 men and 50 women).

    Step 2: Calculate the number of unemployed men and women:
    - Number of unemployed men = 20% of 50 = 10
    - Number of unemployed women = 50% of 50 = 25

    Step 3: Calculate the number of employed men and women:
    - Number of employed men = 50 - 10 = 40
    - Number of employed women = 50 - 25 = 25

    Step 4: Calculate the total number of employed people:
    - Total number of employed people = 40 + 25 = 65

    Step 5: Calculate the probability of the selected person being employed:
    - Probability of the selected person being employed = Total number of employed people / Total number of people in the group
    = 65 / 100
    = 0.65

    Therefore, the probability of the selected person being employed is 0.65.
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    A group consists of equal number of men and women. Of this group 20% of the men and 50% of the women are unemployed. If a person is selected at random from this group, the probability of the selected person being employed is _______.Correct answer is '0.65'. Can you explain this answer?
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