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A mixture of ferric oxide(Fe2O3) and Al is used as a solid rocket fuel which reacts to give Al2O3 and Fe.No other reactants and product are involved on complete reaction of 1mole of Fe203,200 units of energy is released (1)write a balance reaction representing the above change (2)What should be the ratio of masses of Fe203 and Al taken so that maximum energy per unit of mass is released (3)What would be energy released if 16kg of fe203 reacts with 2.7kg of Al?
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A mixture of ferric oxide(Fe2O3) and Al is used as a solid rocket fuel...
1) The balanced reaction is as follows:
Moles of
As
2) According to this reaction, if their mole ratio is 1:2, then the energy released will be maximum.
3)
Given:
kg of
and
kg of
Moles of
Moles of
As
is limiting reagent, so only
mol of
reacts with
mol of Al and energy released will be
units.
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A mixture of ferric oxide(Fe2O3) and Al is used as a solid rocket fuel...
1. Balanced Reaction:
The balanced chemical equation representing the reaction of ferric oxide (Fe2O3) and aluminum (Al) to form aluminum oxide (Al2O3) and iron (Fe) is as follows:
2Al + Fe2O3 → Al2O3 + 2Fe
2. Ratio of Masses:
To determine the ratio of masses of Fe2O3 and Al that will result in maximum energy per unit of mass, we need to calculate the molar masses of the compounds involved.
The molar mass of Fe2O3 = (2 x molar mass of Fe) + (3 x molar mass of O)
= (2 x 55.845 g/mol) + (3 x 16.00 g/mol)
= 159.69 g/mol
The molar mass of Al = 26.98 g/mol
Now, let's assume the ratio of masses of Fe2O3 and Al to be x : y. Therefore, we can write the equation:
(x mol Fe2O3) / (y mol Al) = (molar mass of Fe2O3) / (molar mass of Al)
Substituting the values, we have:
(x mol * 159.69 g/mol) / (y mol * 26.98 g/mol) = 1
Simplifying the equation, we get:
(x / y) = (26.98 / 159.69)
Therefore, the ratio of masses of Fe2O3 and Al that will result in maximum energy per unit of mass is approximately 1 : 5.92.
3. Energy Released:
To calculate the energy released when 16 kg of Fe2O3 reacts with 2.7 kg of Al, we need to convert the masses into moles.
Moles of Fe2O3 = (mass of Fe2O3) / (molar mass of Fe2O3)
= (16000 g) / (159.69 g/mol)
= 100.10 mol
Moles of Al = (mass of Al) / (molar mass of Al)
= (2700 g) / (26.98 g/mol)
= 100.15 mol
From the balanced equation, we can see that 2 moles of Al react with 1 mole of Fe2O3 to release 200 units of energy. Therefore, the energy released when 100.10 mol of Fe2O3 reacts with 100.15 mol of Al can be calculated using the ratio:
Energy released = (100.10 mol Fe2O3) * (200 units/mol) = 20,020 units
Therefore, if 16 kg of Fe2O3 reacts with 2.7 kg of Al, the energy released will be 20,020 units.
The balanced chemical equation representing the reaction of ferric oxide (Fe2O3) and aluminum (Al) to form aluminum oxide (Al2O3) and iron (Fe) is as follows:
2Al + Fe2O3 → Al2O3 + 2Fe
2. Ratio of Masses:
To determine the ratio of masses of Fe2O3 and Al that will result in maximum energy per unit of mass, we need to calculate the molar masses of the compounds involved.
The molar mass of Fe2O3 = (2 x molar mass of Fe) + (3 x molar mass of O)
= (2 x 55.845 g/mol) + (3 x 16.00 g/mol)
= 159.69 g/mol
The molar mass of Al = 26.98 g/mol
Now, let's assume the ratio of masses of Fe2O3 and Al to be x : y. Therefore, we can write the equation:
(x mol Fe2O3) / (y mol Al) = (molar mass of Fe2O3) / (molar mass of Al)
Substituting the values, we have:
(x mol * 159.69 g/mol) / (y mol * 26.98 g/mol) = 1
Simplifying the equation, we get:
(x / y) = (26.98 / 159.69)
Therefore, the ratio of masses of Fe2O3 and Al that will result in maximum energy per unit of mass is approximately 1 : 5.92.
3. Energy Released:
To calculate the energy released when 16 kg of Fe2O3 reacts with 2.7 kg of Al, we need to convert the masses into moles.
Moles of Fe2O3 = (mass of Fe2O3) / (molar mass of Fe2O3)
= (16000 g) / (159.69 g/mol)
= 100.10 mol
Moles of Al = (mass of Al) / (molar mass of Al)
= (2700 g) / (26.98 g/mol)
= 100.15 mol
From the balanced equation, we can see that 2 moles of Al react with 1 mole of Fe2O3 to release 200 units of energy. Therefore, the energy released when 100.10 mol of Fe2O3 reacts with 100.15 mol of Al can be calculated using the ratio:
Energy released = (100.10 mol Fe2O3) * (200 units/mol) = 20,020 units
Therefore, if 16 kg of Fe2O3 reacts with 2.7 kg of Al, the energy released will be 20,020 units.
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A mixture of ferric oxide(Fe2O3) and Al is used as a solid rocket fuel which reacts to give Al2O3 and Fe.No other reactants and product are involved on complete reaction of 1mole of Fe203,200 units of energy is released (1)write a balance reaction representing the above change (2)What should be the ratio of masses of Fe203 and Al taken so that maximum energy per unit of mass is released (3)What would be energy released if 16kg of fe203 reacts with 2.7kg of Al?
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A mixture of ferric oxide(Fe2O3) and Al is used as a solid rocket fuel which reacts to give Al2O3 and Fe.No other reactants and product are involved on complete reaction of 1mole of Fe203,200 units of energy is released (1)write a balance reaction representing the above change (2)What should be the ratio of masses of Fe203 and Al taken so that maximum energy per unit of mass is released (3)What would be energy released if 16kg of fe203 reacts with 2.7kg of Al? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A mixture of ferric oxide(Fe2O3) and Al is used as a solid rocket fuel which reacts to give Al2O3 and Fe.No other reactants and product are involved on complete reaction of 1mole of Fe203,200 units of energy is released (1)write a balance reaction representing the above change (2)What should be the ratio of masses of Fe203 and Al taken so that maximum energy per unit of mass is released (3)What would be energy released if 16kg of fe203 reacts with 2.7kg of Al? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of ferric oxide(Fe2O3) and Al is used as a solid rocket fuel which reacts to give Al2O3 and Fe.No other reactants and product are involved on complete reaction of 1mole of Fe203,200 units of energy is released (1)write a balance reaction representing the above change (2)What should be the ratio of masses of Fe203 and Al taken so that maximum energy per unit of mass is released (3)What would be energy released if 16kg of fe203 reacts with 2.7kg of Al?.
A mixture of ferric oxide(Fe2O3) and Al is used as a solid rocket fuel which reacts to give Al2O3 and Fe.No other reactants and product are involved on complete reaction of 1mole of Fe203,200 units of energy is released (1)write a balance reaction representing the above change (2)What should be the ratio of masses of Fe203 and Al taken so that maximum energy per unit of mass is released (3)What would be energy released if 16kg of fe203 reacts with 2.7kg of Al? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A mixture of ferric oxide(Fe2O3) and Al is used as a solid rocket fuel which reacts to give Al2O3 and Fe.No other reactants and product are involved on complete reaction of 1mole of Fe203,200 units of energy is released (1)write a balance reaction representing the above change (2)What should be the ratio of masses of Fe203 and Al taken so that maximum energy per unit of mass is released (3)What would be energy released if 16kg of fe203 reacts with 2.7kg of Al? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of ferric oxide(Fe2O3) and Al is used as a solid rocket fuel which reacts to give Al2O3 and Fe.No other reactants and product are involved on complete reaction of 1mole of Fe203,200 units of energy is released (1)write a balance reaction representing the above change (2)What should be the ratio of masses of Fe203 and Al taken so that maximum energy per unit of mass is released (3)What would be energy released if 16kg of fe203 reacts with 2.7kg of Al?.
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