JEE Exam  >  JEE Questions  >  A function f : N → Z defined by f(n) = n... Start Learning for Free
A function f : N → Z defined by f(n) = n - 1/2 when n is odd and f(n) = -n/2 when n is even, is 
  • a)
    one one but not onto
  • b)
    onto but not one one
  • c)
    one one onto
  • d)
    neither one one nor onto
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A function f : N → Z defined by f(n) = n - 1/2when n is odd and f...
f (-1) = 0, f (2) = -1, f (3) = 1, f (4) = -2, f (5) = 2, f (6) = -3,....
∴ f : N → Zis one one onto.
View all questions of this test
Most Upvoted Answer
A function f : N → Z defined by f(n) = n - 1/2when n is odd and f...
It seems like the question is incomplete. Please provide more information about the function f.
Explore Courses for JEE exam
A function f : N → Z defined by f(n) = n - 1/2when n is odd and f(n) = -n/2when n is even, isa)one one but not ontob)onto but not one onec)one one ontod)neither one one nor ontoCorrect answer is option 'C'. Can you explain this answer?
Question Description
A function f : N → Z defined by f(n) = n - 1/2when n is odd and f(n) = -n/2when n is even, isa)one one but not ontob)onto but not one onec)one one ontod)neither one one nor ontoCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A function f : N → Z defined by f(n) = n - 1/2when n is odd and f(n) = -n/2when n is even, isa)one one but not ontob)onto but not one onec)one one ontod)neither one one nor ontoCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A function f : N → Z defined by f(n) = n - 1/2when n is odd and f(n) = -n/2when n is even, isa)one one but not ontob)onto but not one onec)one one ontod)neither one one nor ontoCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A function f : N → Z defined by f(n) = n - 1/2when n is odd and f(n) = -n/2when n is even, isa)one one but not ontob)onto but not one onec)one one ontod)neither one one nor ontoCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A function f : N → Z defined by f(n) = n - 1/2when n is odd and f(n) = -n/2when n is even, isa)one one but not ontob)onto but not one onec)one one ontod)neither one one nor ontoCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A function f : N → Z defined by f(n) = n - 1/2when n is odd and f(n) = -n/2when n is even, isa)one one but not ontob)onto but not one onec)one one ontod)neither one one nor ontoCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A function f : N → Z defined by f(n) = n - 1/2when n is odd and f(n) = -n/2when n is even, isa)one one but not ontob)onto but not one onec)one one ontod)neither one one nor ontoCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A function f : N → Z defined by f(n) = n - 1/2when n is odd and f(n) = -n/2when n is even, isa)one one but not ontob)onto but not one onec)one one ontod)neither one one nor ontoCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A function f : N → Z defined by f(n) = n - 1/2when n is odd and f(n) = -n/2when n is even, isa)one one but not ontob)onto but not one onec)one one ontod)neither one one nor ontoCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev