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Two spring having stiffness constants of 22N/mm and 25N/mm are connected in parallel. They are to be replaced by a single spring to have same effect. The stiffness of that spring will be?
  • a)
    None of the mentioned.
  • b)
    3N/mm
  • c)
    47N/mm
  • d)
    11.7N/mm
Correct answer is option 'C'. Can you explain this answer?
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Two spring having stiffness constants of 22N/mm and 25N/mm are connect...
Explanation: k=22+25.
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Two spring having stiffness constants of 22N/mm and 25N/mm are connect...
To find the stiffness of the single spring that will have the same effect as the two parallel springs, we can use the formula for the equivalent stiffness of springs in parallel:

1/k_eq = 1/k_1 + 1/k_2

where k_eq is the equivalent stiffness and k_1 and k_2 are the stiffness constants of the individual springs.

Given that k_1 = 22 N/mm and k_2 = 25 N/mm, we can substitute these values into the formula:

1/k_eq = 1/22 + 1/25

Now, let's solve for k_eq:

1/k_eq = (25 + 22)/(22 * 25)
= 47/550
= 0.085

To find the stiffness constant of the single spring, we can take the reciprocal of 0.085:

k_eq = 1/0.085
= 11.76 N/mm

Therefore, the stiffness of the single spring that will have the same effect as the two parallel springs is approximately 11.76 N/mm.
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Two spring having stiffness constants of 22N/mm and 25N/mm are connected in parallel. They are to be replaced by a single spring to have same effect. The stiffness of that spring will be?a)None of the mentioned.b)3N/mmc)47N/mmd)11.7N/mmCorrect answer is option 'C'. Can you explain this answer?
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