A shopkeeper buys tea leaves rupees 200 for KG anti dust is @ 120 rupe...
Given:
- Tea leaves bought at ₹200 per kg
- Anti-dust bought at ₹120 per kg in the ratio of 3:5
- Tea leaves sold at 10% profit
- Anti-dust sold at 15% profit
- Total sale is ₹27,000
To find:
- Quantity of tea leaves sold
- Quantity of anti-dust sold
Solution:Let the quantity of tea leaves bought be x kg.
Then, the quantity of anti-dust bought is (5/3)x kg.
Cost Price Calculation:Total cost price = (200 * x) + (120 * 5/3 * x) = (200 + 400) * x = 600x
Selling Price Calculation:Let the selling price of tea leaves be ₹y per kg.
Then, the selling price of anti-dust is ₹(1.15y) per kg.
Now, (3y + 5 * 1.15y) * x = ₹27,000 (Total sale)
Solving the above equation, we get y = ₹280 per kg.
Therefore, the selling price of anti-dust is ₹322 per kg.
Quantity Calculation:Quantity of tea leaves sold = 3/8 * x * (1 + 10/100) = (33/40) * x
Quantity of anti-dust sold = 5/8 * x * (1 + 15/100) = (69/80) * x
Substituting the value of x, we get:
Quantity of tea leaves sold = (33/40) * 1200 = 990 kg
Quantity of anti-dust sold = (69/80) * 1200 = 1035 kg
Answer:
- Quantity of tea leaves sold = 990 kg
- Quantity of anti-dust sold = 1035 kg