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In crystals of which one of the following ionic compounds would you expect maximum distance between centres of cations and anions? [1998]
- a)LiF
- b)CsF
- c)CsI
- d)LiI
Correct answer is option 'C'. Can you explain this answer?
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In crystals of which one of the following ionic compounds would you ex...
As Cs+ ion has larger size than Li+ and I– has larger size than F–, therefore maximum distance between centres of cations and anions is in CsI.
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In crystals of which one of the following ionic compounds would you ex...
The maximum distance between the centers of cations and anions in a crystal is determined by the size of the ions. The larger the size of the ions, the greater the distance between them.
Explanation:
Ionic compounds are made up of positively charged cations and negatively charged anions. In a crystal, the cations and anions are arranged in a regular pattern, with each ion surrounded by ions of the opposite charge.
The distance between the centers of cations and anions is determined by the size of the ions. The larger the size of the ions, the greater the distance between them.
Option A: LiF
Li+ ion has a smaller size than Cs+ ion, and F- ion has a smaller size than I- ion. Therefore, the distance between the centers of cations and anions in LiF crystal will be smaller than that in CsI crystal.
Option B: CsF
Cs+ ion has a larger size than Li+ ion, and F- ion has a smaller size than I- ion. Therefore, the distance between the centers of cations and anions in CsF crystal will be larger than that in LiI crystal.
Option C: CsI
Cs+ ion has a larger size than Li+ ion, and I- ion has a larger size than F- ion. Therefore, the distance between the centers of cations and anions in CsI crystal will be the largest among the given options.
Option D: LiI
Li+ ion has a smaller size than Cs+ ion, and I- ion has a larger size than F- ion. Therefore, the distance between the centers of cations and anions in LiI crystal will be smaller than that in CsI crystal.
Therefore, the correct option is C.
Explanation:
Ionic compounds are made up of positively charged cations and negatively charged anions. In a crystal, the cations and anions are arranged in a regular pattern, with each ion surrounded by ions of the opposite charge.
The distance between the centers of cations and anions is determined by the size of the ions. The larger the size of the ions, the greater the distance between them.
Option A: LiF
Li+ ion has a smaller size than Cs+ ion, and F- ion has a smaller size than I- ion. Therefore, the distance between the centers of cations and anions in LiF crystal will be smaller than that in CsI crystal.
Option B: CsF
Cs+ ion has a larger size than Li+ ion, and F- ion has a smaller size than I- ion. Therefore, the distance between the centers of cations and anions in CsF crystal will be larger than that in LiI crystal.
Option C: CsI
Cs+ ion has a larger size than Li+ ion, and I- ion has a larger size than F- ion. Therefore, the distance between the centers of cations and anions in CsI crystal will be the largest among the given options.
Option D: LiI
Li+ ion has a smaller size than Cs+ ion, and I- ion has a larger size than F- ion. Therefore, the distance between the centers of cations and anions in LiI crystal will be smaller than that in CsI crystal.
Therefore, the correct option is C.
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In crystals of which one of the following ionic compounds would you expect maximum distance between centres of cations and anions? [1998]a)LiFb)CsFc)CsId)LiICorrect answer is option 'C'. Can you explain this answer?
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