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Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of air
D =0.82 * 10 -6 m2/s
v = 15.5 * 10 -6 m2/s
D =0.82 * 10 -6 m2/s
v = 15.5 * 10 -6 m2/s
- a)0.0176 m/s
- b)1.0176 m/s
- c)2.0176 m/s
- d)3.0176 m/s
Correct answer is option 'A'. Can you explain this answer?
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Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm di...
Explanation: h m = (Sherwood number) D/d =0.0176 m/s.
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Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm di...
Given data:
- Air pressure (P) = 1 atm
- Air temperature (T) = 25°C = 298 K
- Tube diameter (D) = 3 cm = 0.03 m
- Air velocity (v) = 5.25 m/s
- Diffusivity of iodine in air (D) = 0.82 * 10^(-6) m^2/s
- Kinematic viscosity of air (v) = 15.5 * 10^(-6) m^2/s
To determine the mass transfer coefficient for iodine transfer from the air stream to the weak surface, we need to use the Sherwood number (Sh) correlation which relates the mass transfer coefficient (k) with the flow conditions and geometry of the system.
The Sherwood number correlation for flow inside a tube is given by:
Sh = 0.023 * Re^0.8 * Sc^(1/3)
Where:
- Re is the Reynolds number, given by Re = (ρ * v * D) / μ
- Sc is the Schmidt number, given by Sc = μ / (ρ * D)
ρ is the density of air, which can be calculated using the ideal gas law:
ρ = P / (R * T)
Where R is the universal gas constant.
Calculations:
1. Calculate the density of air:
R = 0.0821 L.atm/(mol.K) (universal gas constant)
P = 1 atm
T = 298 K
ρ = P / (R * T) = 1 / (0.0821 * 298) = 1.322 kg/m^3
2. Calculate the Reynolds number:
μ = v / ρ = 15.5 * 10^(-6) / 1.322 = 11.73 * 10^(-6) m^2/s
Re = (ρ * v * D) / μ = (1.322 * 5.25 * 0.03) / (11.73 * 10^(-6)) = 17,703.14
3. Calculate the Schmidt number:
Sc = μ / (ρ * D) = (15.5 * 10^(-6)) / (1.322 * 0.03) = 391.49
4. Calculate the Sherwood number:
Sh = 0.023 * Re^0.8 * Sc^(1/3) = 0.023 * (17,703.14)^0.8 * (391.49)^(1/3) = 31.84
5. Calculate the mass transfer coefficient:
k = Sh * D / L = 31.84 * 0.03 / 0.03 = 31.84 * 10^(-3) m/s
Therefore, the mass transfer coefficient for iodine transfer from the air stream to the weak surface is approximately 0.03184 m/s, which corresponds to option 'A'.
- Air pressure (P) = 1 atm
- Air temperature (T) = 25°C = 298 K
- Tube diameter (D) = 3 cm = 0.03 m
- Air velocity (v) = 5.25 m/s
- Diffusivity of iodine in air (D) = 0.82 * 10^(-6) m^2/s
- Kinematic viscosity of air (v) = 15.5 * 10^(-6) m^2/s
To determine the mass transfer coefficient for iodine transfer from the air stream to the weak surface, we need to use the Sherwood number (Sh) correlation which relates the mass transfer coefficient (k) with the flow conditions and geometry of the system.
The Sherwood number correlation for flow inside a tube is given by:
Sh = 0.023 * Re^0.8 * Sc^(1/3)
Where:
- Re is the Reynolds number, given by Re = (ρ * v * D) / μ
- Sc is the Schmidt number, given by Sc = μ / (ρ * D)
ρ is the density of air, which can be calculated using the ideal gas law:
ρ = P / (R * T)
Where R is the universal gas constant.
Calculations:
1. Calculate the density of air:
R = 0.0821 L.atm/(mol.K) (universal gas constant)
P = 1 atm
T = 298 K
ρ = P / (R * T) = 1 / (0.0821 * 298) = 1.322 kg/m^3
2. Calculate the Reynolds number:
μ = v / ρ = 15.5 * 10^(-6) / 1.322 = 11.73 * 10^(-6) m^2/s
Re = (ρ * v * D) / μ = (1.322 * 5.25 * 0.03) / (11.73 * 10^(-6)) = 17,703.14
3. Calculate the Schmidt number:
Sc = μ / (ρ * D) = (15.5 * 10^(-6)) / (1.322 * 0.03) = 391.49
4. Calculate the Sherwood number:
Sh = 0.023 * Re^0.8 * Sc^(1/3) = 0.023 * (17,703.14)^0.8 * (391.49)^(1/3) = 31.84
5. Calculate the mass transfer coefficient:
k = Sh * D / L = 31.84 * 0.03 / 0.03 = 31.84 * 10^(-3) m/s
Therefore, the mass transfer coefficient for iodine transfer from the air stream to the weak surface is approximately 0.03184 m/s, which corresponds to option 'A'.
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Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of airD =0.82 * 10 -6 m2/sv = 15.5 * 10 -6 m2/sa)0.0176 m/sb)1.0176 m/sc)2.0176 m/sd)3.0176 m/sCorrect answer is option 'A'. Can you explain this answer?
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Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of airD =0.82 * 10 -6 m2/sv = 15.5 * 10 -6 m2/sa)0.0176 m/sb)1.0176 m/sc)2.0176 m/sd)3.0176 m/sCorrect answer is option 'A'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of airD =0.82 * 10 -6 m2/sv = 15.5 * 10 -6 m2/sa)0.0176 m/sb)1.0176 m/sc)2.0176 m/sd)3.0176 m/sCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of airD =0.82 * 10 -6 m2/sv = 15.5 * 10 -6 m2/sa)0.0176 m/sb)1.0176 m/sc)2.0176 m/sd)3.0176 m/sCorrect answer is option 'A'. Can you explain this answer?.
Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of airD =0.82 * 10 -6 m2/sv = 15.5 * 10 -6 m2/sa)0.0176 m/sb)1.0176 m/sc)2.0176 m/sd)3.0176 m/sCorrect answer is option 'A'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of airD =0.82 * 10 -6 m2/sv = 15.5 * 10 -6 m2/sa)0.0176 m/sb)1.0176 m/sc)2.0176 m/sd)3.0176 m/sCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of airD =0.82 * 10 -6 m2/sv = 15.5 * 10 -6 m2/sa)0.0176 m/sb)1.0176 m/sc)2.0176 m/sd)3.0176 m/sCorrect answer is option 'A'. Can you explain this answer?.
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Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of airD =0.82 * 10 -6 m2/sv = 15.5 * 10 -6 m2/sa)0.0176 m/sb)1.0176 m/sc)2.0176 m/sd)3.0176 m/sCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of airD =0.82 * 10 -6 m2/sv = 15.5 * 10 -6 m2/sa)0.0176 m/sb)1.0176 m/sc)2.0176 m/sd)3.0176 m/sCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of airD =0.82 * 10 -6 m2/sv = 15.5 * 10 -6 m2/sa)0.0176 m/sb)1.0176 m/sc)2.0176 m/sd)3.0176 m/sCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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