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Two forces each equal to F theta is 60 degrees , their resultant is?
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Two forces each equal to F theta is 60 degrees , their resultant is?
Calculation of Resultant Force of Two Forces at 60 degrees


Given Information


  • Two forces each equal to F

  • The angle between the forces is 60 degrees



Step-by-Step Solution


  1. First, find the horizontal and vertical components of each force:


    • The horizontal component of F is F cos 60 degrees = 0.5F

    • The vertical component of F is F sin 60 degrees = (sqrt(3)/2)F


  2. Next, find the horizontal and vertical components of the other force:


    • The horizontal component of F is F cos 60 degrees = 0.5F

    • The vertical component of F is -F sin 60 degrees = -(sqrt(3)/2)F


  3. Add the horizontal and vertical components of each force separately:


    • Horizontal component = 0.5F + 0.5F = F

    • Vertical component = (sqrt(3)/2)F - (sqrt(3)/2)F = 0


  4. Using the Pythagorean theorem, find the magnitude of the resultant force:


    • Magnitude of the resultant force = sqrt((F)^2 + (0)^2) = F


  5. Find the angle of the resultant force:


    • The angle of the resultant force is tan inverse (0/F) = 0 degrees


  6. The resultant force is F and its direction is horizontal.



Conclusion


  • The resultant force of two forces each equal to F at 60 degrees is F, and its direction is horizontal.

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Two forces each equal to F theta is 60 degrees , their resultant is?
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