A committee of 5 is to be formed from 6 boys and 5 girls. The number o...
To solve this problem, we can use the concept of combinations.
We want to form a committee of 5 members with at least one boy and one girl.
Step 1: Calculate the total number of ways to form a committee of 5 members from the given 11 candidates.
The total number of ways to select 5 members from 11 candidates is given by the combination formula:
C(11, 5) = 11! / (5! * (11 - 5)!) = 11! / (5! * 6!) = (11 * 10 * 9 * 8 * 7) / (5 * 4 * 3 * 2 * 1) = 462
Therefore, there are 462 ways to form a committee of 5 members from the given candidates.
Step 2: Calculate the number of ways to form a committee with only boys.
Since there are 6 boys and we need to select 5 members, we can directly use the combination formula:
C(6, 5) = 6! / (5! * (6 - 5)!) = 6! / (5! * 1!) = 6
Therefore, there are 6 ways to form a committee with only boys.
Step 3: Calculate the number of ways to form a committee with only girls.
Since there are 5 girls and we need to select 5 members, we can directly use the combination formula:
C(5, 5) = 5! / (5! * (5 - 5)!) = 5! / (5! * 0!) = 1
Therefore, there is 1 way to form a committee with only girls.
Step 4: Calculate the number of ways to form a committee with at least one boy and one girl.
To find the number of ways to form a committee with at least one boy and one girl, we subtract the number of ways to form a committee with only boys or only girls from the total number of ways.
Number of ways = Total number of ways - Number of ways with only boys - Number of ways with only girls
= 462 - 6 - 1
= 455
Therefore, the number of ways to form a committee with at least one boy and one girl, having a majority of boys, is 455.
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