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An initially parallel cylindrical beam travels in a medium of refractive index μ (I) = μ0 + μ2 I, where μ0 and μ2 are positive constants and I is the intensity of the light beam. The intensity of the beam is decreasing with increasing radius.
Q. As the beam enters the medium , it will
- a)diverge
- b)con verge
- c)diverge near the axis and converge near the periphery
- d)travel as a cylindrical beam
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
An initially parallel cylindrical beam travels in a medium of refracti...
In the medium, the refractive index will decrease from the axis towards the periphery of the beam.
Therefore, the beam will move as one move from the axis to the periphery and hence the beam will converge.
Therefore, the beam will move as one move from the axis to the periphery and hence the beam will converge.
Most Upvoted Answer
An initially parallel cylindrical beam travels in a medium of refracti...
In order to find the angle of refraction, we can use Snell's law:
n1 * sin(theta1) = n2 * sin(theta2)
Where:
n1 = refractive index of the medium the beam is initially traveling in
theta1 = angle of incidence (measured from the normal to the surface)
n2 = refractive index of the medium the beam enters
theta2 = angle of refraction (measured from the normal to the surface)
Since the beam is initially parallel to the surface, the angle of incidence, theta1, would be 0 degrees. We can simplify Snell's law in this case to:
n1 * sin(0) = n2 * sin(theta2)
Since sin(0) is 0, the left side of the equation becomes 0:
0 = n2 * sin(theta2)
This means that the angle of refraction, theta2, would also be 0 degrees.
n1 * sin(theta1) = n2 * sin(theta2)
Where:
n1 = refractive index of the medium the beam is initially traveling in
theta1 = angle of incidence (measured from the normal to the surface)
n2 = refractive index of the medium the beam enters
theta2 = angle of refraction (measured from the normal to the surface)
Since the beam is initially parallel to the surface, the angle of incidence, theta1, would be 0 degrees. We can simplify Snell's law in this case to:
n1 * sin(0) = n2 * sin(theta2)
Since sin(0) is 0, the left side of the equation becomes 0:
0 = n2 * sin(theta2)
This means that the angle of refraction, theta2, would also be 0 degrees.
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An initially parallel cylindrical beam travels in a medium of refractive index μ (I) = μ0 + μ2 I, where μ0 and μ2 are positive constants and I is the intensity of the light beam. The intensity of the beam is decreasing with increasing radius.Q.As the beam enters the medium , it willa)divergeb)con vergec)diverge near the axis and converge near the peripheryd)travel as a cylindrical beamCorrect answer is option 'B'. Can you explain this answer?
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An initially parallel cylindrical beam travels in a medium of refractive index μ (I) = μ0 + μ2 I, where μ0 and μ2 are positive constants and I is the intensity of the light beam. The intensity of the beam is decreasing with increasing radius.Q.As the beam enters the medium , it willa)divergeb)con vergec)diverge near the axis and converge near the peripheryd)travel as a cylindrical beamCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An initially parallel cylindrical beam travels in a medium of refractive index μ (I) = μ0 + μ2 I, where μ0 and μ2 are positive constants and I is the intensity of the light beam. The intensity of the beam is decreasing with increasing radius.Q.As the beam enters the medium , it willa)divergeb)con vergec)diverge near the axis and converge near the peripheryd)travel as a cylindrical beamCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An initially parallel cylindrical beam travels in a medium of refractive index μ (I) = μ0 + μ2 I, where μ0 and μ2 are positive constants and I is the intensity of the light beam. The intensity of the beam is decreasing with increasing radius.Q.As the beam enters the medium , it willa)divergeb)con vergec)diverge near the axis and converge near the peripheryd)travel as a cylindrical beamCorrect answer is option 'B'. Can you explain this answer?.
An initially parallel cylindrical beam travels in a medium of refractive index μ (I) = μ0 + μ2 I, where μ0 and μ2 are positive constants and I is the intensity of the light beam. The intensity of the beam is decreasing with increasing radius.Q.As the beam enters the medium , it willa)divergeb)con vergec)diverge near the axis and converge near the peripheryd)travel as a cylindrical beamCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An initially parallel cylindrical beam travels in a medium of refractive index μ (I) = μ0 + μ2 I, where μ0 and μ2 are positive constants and I is the intensity of the light beam. The intensity of the beam is decreasing with increasing radius.Q.As the beam enters the medium , it willa)divergeb)con vergec)diverge near the axis and converge near the peripheryd)travel as a cylindrical beamCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An initially parallel cylindrical beam travels in a medium of refractive index μ (I) = μ0 + μ2 I, where μ0 and μ2 are positive constants and I is the intensity of the light beam. The intensity of the beam is decreasing with increasing radius.Q.As the beam enters the medium , it willa)divergeb)con vergec)diverge near the axis and converge near the peripheryd)travel as a cylindrical beamCorrect answer is option 'B'. Can you explain this answer?.
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