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 Recursively enumerable languages are not closed under:
  • a)
    Union
  • b)
    Intersection
  • c)
    Complementation
  • d)
    Concatenation
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Recursively enumerable languages are not closed under:a)Unionb)Interse...
Recursive languages are closed under the following operations.
The Kleene star L * of L
the concatenation L * o P of L and P
the union L U P
the intersection L ∩ P.
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Recursively enumerable languages are not closed under:a)Unionb)Interse...
Recursively Enumerable Languages and Complementation

Recursively Enumerable Languages (also known as recursively enumerable sets or Type-0 languages) are a class of languages in theoretical computer science. A language is considered recursively enumerable if there exists a Turing machine that can enumerate (list) all the strings in that language.

Complementation refers to taking the complement of a language, which means considering all the strings that are not in the language. In other words, if L is a language, then the complement of L, denoted as L', contains all the strings that are not in L.

Recursively Enumerable Languages and Closure Properties

Closure properties refer to the properties of a class of languages that determine whether the class is closed under certain operations. If a class of languages is closed under a particular operation, it means that if the languages in the class satisfy certain criteria, then the result of applying that operation to those languages will also be in the same class.

In the case of recursively enumerable languages, they are not closed under complementation. This means that if a language L is recursively enumerable, its complement L' is not necessarily recursively enumerable. In other words, there is no guarantee that the Turing machine that enumerates the strings in L can also enumerate the strings in L'.

Explanation of why Recursively Enumerable Languages are not closed under Complementation

The reason why recursively enumerable languages are not closed under complementation can be understood by considering the behavior of Turing machines.

A Turing machine that enumerates the strings in a recursively enumerable language can potentially run forever on inputs that are not in the language. This is because the machine has to enumerate all the strings in the language, and there is no guarantee that it will halt on inputs that are not in the language.

Now, if we consider the complement of a recursively enumerable language, we would need a Turing machine that can enumerate all the strings that are not in the language. However, since the original Turing machine for the language may run forever on inputs that are not in the language, we cannot guarantee that the complement Turing machine will halt on inputs that are in the complement language.

Therefore, we cannot construct a Turing machine that can enumerate all the strings in the complement of a recursively enumerable language, which means that recursively enumerable languages are not closed under complementation.

Conclusion

In conclusion, recursively enumerable languages are not closed under complementation. This means that if a language L is recursively enumerable, its complement L' is not necessarily recursively enumerable. The reason for this is that the Turing machine that enumerates the strings in a recursively enumerable language may not halt on inputs that are not in the language, making it impossible to construct a Turing machine that can enumerate all the strings in the complement language.
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Recursively enumerable languages are not closed under:a)Unionb)Intersectionc)Complementationd)ConcatenationCorrect answer is option 'C'. Can you explain this answer?
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