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Light guidance in an optical fibre can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2.
The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sin im.
Q. For two structure namely S1 with  and n2 = 3/2, and S2 with n1 = 8/5 and n2 = 7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)
  • a)
    NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive index 
  • b)
    NA of S1 immersed in liquid of refractive index  is the same as that of S2 immersed in water
  • c)
    NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive index 
  • d)
    NA of S1 placed in air is the same as that of S2 placed in water
Correct answer is option 'A,C'. Can you explain this answer?
Verified Answer
Light guidance in an optical fibre can be understood by considering a ...
Applying Snell’s law at P; ns sin im = n1 sin (90° – C) ns = Refractive index of surrounding
(a), (c) are correct options
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Light guidance in an optical fibre can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2.The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sin im.Q.For two structure namely S1 withand n2 = 3/2, and S2 with n1 = 8/5 and n2 = 7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)a)NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive indexb)NA of S1 immersed in liquid of refractive indexis the same as that of S2 immersed in waterc)NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive indexd)NA of S1 placed in air is the same as that of S2 placed in waterCorrect answer is option 'A,C'. Can you explain this answer?
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Light guidance in an optical fibre can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2.The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sin im.Q.For two structure namely S1 withand n2 = 3/2, and S2 with n1 = 8/5 and n2 = 7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)a)NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive indexb)NA of S1 immersed in liquid of refractive indexis the same as that of S2 immersed in waterc)NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive indexd)NA of S1 placed in air is the same as that of S2 placed in waterCorrect answer is option 'A,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Light guidance in an optical fibre can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2.The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sin im.Q.For two structure namely S1 withand n2 = 3/2, and S2 with n1 = 8/5 and n2 = 7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)a)NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive indexb)NA of S1 immersed in liquid of refractive indexis the same as that of S2 immersed in waterc)NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive indexd)NA of S1 placed in air is the same as that of S2 placed in waterCorrect answer is option 'A,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Light guidance in an optical fibre can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2.The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sin im.Q.For two structure namely S1 withand n2 = 3/2, and S2 with n1 = 8/5 and n2 = 7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)a)NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive indexb)NA of S1 immersed in liquid of refractive indexis the same as that of S2 immersed in waterc)NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive indexd)NA of S1 placed in air is the same as that of S2 placed in waterCorrect answer is option 'A,C'. Can you explain this answer?.
Solutions for Light guidance in an optical fibre can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2.The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sin im.Q.For two structure namely S1 withand n2 = 3/2, and S2 with n1 = 8/5 and n2 = 7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)a)NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive indexb)NA of S1 immersed in liquid of refractive indexis the same as that of S2 immersed in waterc)NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive indexd)NA of S1 placed in air is the same as that of S2 placed in waterCorrect answer is option 'A,C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Light guidance in an optical fibre can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2.The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sin im.Q.For two structure namely S1 withand n2 = 3/2, and S2 with n1 = 8/5 and n2 = 7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)a)NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive indexb)NA of S1 immersed in liquid of refractive indexis the same as that of S2 immersed in waterc)NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive indexd)NA of S1 placed in air is the same as that of S2 placed in waterCorrect answer is option 'A,C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Light guidance in an optical fibre can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2.The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sin im.Q.For two structure namely S1 withand n2 = 3/2, and S2 with n1 = 8/5 and n2 = 7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)a)NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive indexb)NA of S1 immersed in liquid of refractive indexis the same as that of S2 immersed in waterc)NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive indexd)NA of S1 placed in air is the same as that of S2 placed in waterCorrect answer is option 'A,C'. Can you explain this answer?, a detailed solution for Light guidance in an optical fibre can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2.The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sin im.Q.For two structure namely S1 withand n2 = 3/2, and S2 with n1 = 8/5 and n2 = 7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)a)NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive indexb)NA of S1 immersed in liquid of refractive indexis the same as that of S2 immersed in waterc)NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive indexd)NA of S1 placed in air is the same as that of S2 placed in waterCorrect answer is option 'A,C'. Can you explain this answer? has been provided alongside types of Light guidance in an optical fibre can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2.The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sin im.Q.For two structure namely S1 withand n2 = 3/2, and S2 with n1 = 8/5 and n2 = 7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)a)NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive indexb)NA of S1 immersed in liquid of refractive indexis the same as that of S2 immersed in waterc)NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive indexd)NA of S1 placed in air is the same as that of S2 placed in waterCorrect answer is option 'A,C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Light guidance in an optical fibre can be understood by considering a structure comprising of thin solid glass cylinder of refractive index n1 surrounded by a medium of lower refractive index n2.The light guidance in the structure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown in the figure. All rays with the angle of incidence i less than a particular value im are confined in the medium of refractive index n1. The numerical aperture (NA) of the structure is defined as sin im.Q.For two structure namely S1 withand n2 = 3/2, and S2 with n1 = 8/5 and n2 = 7/5 and taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)a)NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive indexb)NA of S1 immersed in liquid of refractive indexis the same as that of S2 immersed in waterc)NA of S1 placed in air is the same as that of S2 immersed in liquid of refractive indexd)NA of S1 placed in air is the same as that of S2 placed in waterCorrect answer is option 'A,C'. Can you explain this answer? tests, examples and also practice JEE tests.
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