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The stablest among the following is [1994]
- a)CH3CH(OH)2
- b)ClCH2CH(OH)2
- c)(CH3)2 C (OH)2
- d)CCl3 CH (OH)2.
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The stablest among the following is [1994]a)CH3CH(OH)2b)ClCH2CH(OH)2c)...
Due to –I-effect of the three C–Cl-bonding between CI and C-atom of the OH group, CCl3 CH (OH)2 is most stable.
Most Upvoted Answer
The stablest among the following is [1994]a)CH3CH(OH)2b)ClCH2CH(OH)2c)...
Chlorine show minus I effect. so, the greater the number of chlorine atom, more is the dispersal of charge of oxygen atom.
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The stablest among the following is [1994]a)CH3CH(OH)2b)ClCH2CH(OH)2c)...
The stability of a compound can be determined by analyzing its structure and the stability of its functional groups. In this case, we are comparing four compounds and trying to identify the most stable one among them.
a) CH3CH(OH)2
b) ClCH2CH(OH)2
c) (CH3)2C(OH)2
d) CCl3CH(OH)2
To determine the stability of these compounds, we need to consider the factors that contribute to stability, such as electron density, steric hindrance, and the presence of electron-withdrawing or electron-donating groups.
1. Electron Density:
The stability of a compound can be influenced by the electron density around its functional groups. Compounds with electron-donating groups tend to be more stable compared to those with electron-withdrawing groups. In this case, all four compounds have the same functional group, which is the hydroxyl group (-OH). Therefore, the electron density factor does not play a significant role in determining their stability.
2. Steric Hindrance:
Steric hindrance refers to the interference between bulky substituents, which can affect the stability of a compound. Compounds with less steric hindrance are generally more stable. Let's analyze each compound to determine the level of steric hindrance:
a) CH3CH(OH)2: This compound has two methyl groups attached to the central carbon atom. The methyl groups are relatively small, so there is minimal steric hindrance.
b) ClCH2CH(OH)2: This compound has a chlorine atom attached to the central carbon atom. Chlorine is larger than a methyl group, so there is some steric hindrance.
c) (CH3)2C(OH)2: This compound has two methyl groups attached to the central carbon atom. Similar to compound a, there is minimal steric hindrance.
d) CCl3CH(OH)2: This compound has three chlorine atoms attached to the central carbon atom. Chlorine is larger than a methyl group, so there is significant steric hindrance.
Based on the analysis of steric hindrance, it can be concluded that compound d (CCl3CH(OH)2) has the highest steric hindrance among the four compounds, making it the least stable.
Therefore, the correct answer is option d) CCl3CH(OH)2, which is the least stable compound among the given options.
a) CH3CH(OH)2
b) ClCH2CH(OH)2
c) (CH3)2C(OH)2
d) CCl3CH(OH)2
To determine the stability of these compounds, we need to consider the factors that contribute to stability, such as electron density, steric hindrance, and the presence of electron-withdrawing or electron-donating groups.
1. Electron Density:
The stability of a compound can be influenced by the electron density around its functional groups. Compounds with electron-donating groups tend to be more stable compared to those with electron-withdrawing groups. In this case, all four compounds have the same functional group, which is the hydroxyl group (-OH). Therefore, the electron density factor does not play a significant role in determining their stability.
2. Steric Hindrance:
Steric hindrance refers to the interference between bulky substituents, which can affect the stability of a compound. Compounds with less steric hindrance are generally more stable. Let's analyze each compound to determine the level of steric hindrance:
a) CH3CH(OH)2: This compound has two methyl groups attached to the central carbon atom. The methyl groups are relatively small, so there is minimal steric hindrance.
b) ClCH2CH(OH)2: This compound has a chlorine atom attached to the central carbon atom. Chlorine is larger than a methyl group, so there is some steric hindrance.
c) (CH3)2C(OH)2: This compound has two methyl groups attached to the central carbon atom. Similar to compound a, there is minimal steric hindrance.
d) CCl3CH(OH)2: This compound has three chlorine atoms attached to the central carbon atom. Chlorine is larger than a methyl group, so there is significant steric hindrance.
Based on the analysis of steric hindrance, it can be concluded that compound d (CCl3CH(OH)2) has the highest steric hindrance among the four compounds, making it the least stable.
Therefore, the correct answer is option d) CCl3CH(OH)2, which is the least stable compound among the given options.
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