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Consider the following proposed solution for the two – process synchronization.
Code for P0:
do
{flag[0] = true;
turn = 1;
while(flag[1] && turn == 1);
(critical section)
 flag[0] = false;
                (remainder section)
 }
 while(true);
 
 Code for P1:
 do
{flag[1] = true;
turn = 0;
while(flag[0] && turn == 0);
(critical section)
 flag[1] = false;
                (remainder section)
 }
 while(true);
Above solution requires two shared data items: turn and flag[]
The variable turn indicates whose turn it is to enter its critical section. The flag array is used to indicate if a process is ready to enter its critical section.
Which of the following statement is TRUE?
  • a)
    ​Above solution violates mutual exclusion property.
  • b)
    Above solution violates progress requirement.
  • c)
    Above solution violates bounded wait requirement.
  • d)
    Above solution is a correct two process synchronization solution.
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Consider the following proposed solution for the two – process s...
P0 and P1 could not have successfully executed their while statements at about the same time, since the value of turn can be either 0 or 1 but cannot be both. Hence, one of the processes say, P1 must have successfully executed the while statement, whereas P0 had to execute at least one additional statement. Hence mutual exclusion is preserved.
Once P1 exits its critical section, it will reset flag[1] to false, allowing P0 to enter its critical section. If P1 resets flag[1] to true, it must also set turn to 0. Thus, since P0 does not change the value of the variable turn while executing the while statement, P0 will enter the critical section (progress) after at most one entry by P1 (bounded waiting).
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Most Upvoted Answer
Consider the following proposed solution for the two – process s...
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Consider the following proposed solution for the two – process synchronization.Code for P0:do{flag[0] = true;turn = 1;while(flag[1] && turn == 1);(critical section)flag[0] = false; (remainder section)}while(true);Code for P1:do{flag[1] = true;turn = 0;while(flag[0] && turn == 0);(critical section)flag[1] = false; (remainder section)}while(true);Above solution requires two shared data items: turn and flag[]The variable turn indicates whose turn it is to enter its critical section. The flag array is used to indicate if a process is ready to enter its critical section.Which of the following statement is TRUE?a)​Above solution violates mutual exclusion property.b)Above solution violates progress requirement.c)Above solution violates bounded wait requirement.d)Above solution is a correct two process synchronization solution.Correct answer is option 'D'. Can you explain this answer?
Question Description
Consider the following proposed solution for the two – process synchronization.Code for P0:do{flag[0] = true;turn = 1;while(flag[1] && turn == 1);(critical section)flag[0] = false; (remainder section)}while(true);Code for P1:do{flag[1] = true;turn = 0;while(flag[0] && turn == 0);(critical section)flag[1] = false; (remainder section)}while(true);Above solution requires two shared data items: turn and flag[]The variable turn indicates whose turn it is to enter its critical section. The flag array is used to indicate if a process is ready to enter its critical section.Which of the following statement is TRUE?a)​Above solution violates mutual exclusion property.b)Above solution violates progress requirement.c)Above solution violates bounded wait requirement.d)Above solution is a correct two process synchronization solution.Correct answer is option 'D'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider the following proposed solution for the two – process synchronization.Code for P0:do{flag[0] = true;turn = 1;while(flag[1] && turn == 1);(critical section)flag[0] = false; (remainder section)}while(true);Code for P1:do{flag[1] = true;turn = 0;while(flag[0] && turn == 0);(critical section)flag[1] = false; (remainder section)}while(true);Above solution requires two shared data items: turn and flag[]The variable turn indicates whose turn it is to enter its critical section. The flag array is used to indicate if a process is ready to enter its critical section.Which of the following statement is TRUE?a)​Above solution violates mutual exclusion property.b)Above solution violates progress requirement.c)Above solution violates bounded wait requirement.d)Above solution is a correct two process synchronization solution.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following proposed solution for the two – process synchronization.Code for P0:do{flag[0] = true;turn = 1;while(flag[1] && turn == 1);(critical section)flag[0] = false; (remainder section)}while(true);Code for P1:do{flag[1] = true;turn = 0;while(flag[0] && turn == 0);(critical section)flag[1] = false; (remainder section)}while(true);Above solution requires two shared data items: turn and flag[]The variable turn indicates whose turn it is to enter its critical section. The flag array is used to indicate if a process is ready to enter its critical section.Which of the following statement is TRUE?a)​Above solution violates mutual exclusion property.b)Above solution violates progress requirement.c)Above solution violates bounded wait requirement.d)Above solution is a correct two process synchronization solution.Correct answer is option 'D'. Can you explain this answer?.
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