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Alan has two more than twice as many chocolates as does Alice, and half as many chocolates as does Nadia. If Alice has ‘a’ number of chocolates, then in terms of ‘a’, how many chocolates do Alan, Alice and Nadia have?
  • a)
    2a+ 4
  • b)
    5a+5
  • c)
    6a+7
  • d)
    7a+6
  • e)
    9a+4
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Alan has two more than twice as many chocolates as does Alice, and hal...
We know that Alice has 'a' chocolates. Alan has 2a+2 chocolates from the given statement in the question. Nadia has double the chocolates as Alan has, so she has 4a+4 chocolates.
Adding these, we get 4a+4+2a+2+a = 7a +6 . So ,Option (d) is correct.
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Most Upvoted Answer
Alan has two more than twice as many chocolates as does Alice, and hal...
X chocolates, then Alan has 2x+2 chocolates, and Nadia has 2*(2x+2)=4x+4 chocolates. Therefore, we have:

2x+2 = (1/2)(4x+4)
Multiplying both sides by 2:
4x+4 = 4x+4
Subtracting 4x from both sides:
4 = 4

This equation is always true, meaning that there are infinitely many possible values for x, the number of chocolates Alice has. Therefore, we cannot determine the exact number of chocolates each person has without additional information.
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