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One g of a mixture of Na2CO3 and NaHCO3 consumes y equivalent of HCI for complete neutralisation. One g of the mixture is strongly heated, then cooled and the residue treated with HCI how many equivalent of HCI would be required for com-plete neutralisation?
- a)2y equivalent
- b)y equivalent
- c)3y/4 equivalent
- d)3y/2 equivalent
Correct answer is option 'B'. Can you explain this answer?
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One g of a mixture of Na2CO3 and NaHCO3 consumes y equivalent of HCI f...
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One g of a mixture of Na2CO3 and NaHCO3 consumes y equivalent of HCI f...
Given:
- 1 g of a mixture of Na2CO3 and NaHCO3 consumes y equivalent of HCI for complete neutralisation.
- The mixture is heated, cooled and the residue treated with HCI.
To find: How many equivalent of HCI would be required for complete neutralisation?
Solution:
1. Calculation of equivalent weight of Na2CO3 and NaHCO3
- Na2CO3 reacts with 2 moles of HCl to form 2 moles of NaCl and 1 mole of CO2.
- NaHCO3 reacts with 1 mole of HCl to form 1 mole of NaCl, 1 mole of CO2 and 1 mole of H2O.
- The equivalent weight of Na2CO3 and NaHCO3 can be calculated as follows:
- For Na2CO3, equivalent weight = molar mass / number of acidic hydrogens = 106 / 2 = 53 g/equivalent
- For NaHCO3, equivalent weight = molar mass / number of acidic hydrogens = 84 / 1 = 84 g/equivalent
2. Calculation of the composition of the mixture
- Let x be the mass of Na2CO3 and (1 - x) be the mass of NaHCO3 in the mixture.
- Then, we have x(53 / 106) + (1 - x)(84 / 84) = 1
- Solving the equation, we get x = 0.5.
- Therefore, the mixture contains 0.5 g of Na2CO3 and 0.5 g of NaHCO3.
3. Calculation of the equivalent weight of the mixture
- The equivalent weight of the mixture can be calculated as follows:
- Equivalent weight of the mixture = (mass of Na2CO3 / equivalent weight of Na2CO3) + (mass of NaHCO3 / equivalent weight of NaHCO3)
- = (0.5 / 53) + (0.5 / 84)
- = 0.0132 + 0.0059
- = 0.0191 g/equivalent
4. Calculation of the number of equivalents of HCI required for complete neutralisation of the residue
- When the mixture is heated, NaHCO3 decomposes to form Na2CO3, CO2 and H2O.
- Therefore, the residue will contain only Na2CO3.
- Since 1 g of the mixture consumes y equivalents of HCI for complete neutralisation, 0.5 g of Na2CO3 will consume y/2 equivalents of HCI for complete neutralisation.
- When the residue is treated with HCI, the number of equivalents of HCI required for complete neutralisation will be y/2.
Therefore, the correct answer is option B, y equivalents.
- 1 g of a mixture of Na2CO3 and NaHCO3 consumes y equivalent of HCI for complete neutralisation.
- The mixture is heated, cooled and the residue treated with HCI.
To find: How many equivalent of HCI would be required for complete neutralisation?
Solution:
1. Calculation of equivalent weight of Na2CO3 and NaHCO3
- Na2CO3 reacts with 2 moles of HCl to form 2 moles of NaCl and 1 mole of CO2.
- NaHCO3 reacts with 1 mole of HCl to form 1 mole of NaCl, 1 mole of CO2 and 1 mole of H2O.
- The equivalent weight of Na2CO3 and NaHCO3 can be calculated as follows:
- For Na2CO3, equivalent weight = molar mass / number of acidic hydrogens = 106 / 2 = 53 g/equivalent
- For NaHCO3, equivalent weight = molar mass / number of acidic hydrogens = 84 / 1 = 84 g/equivalent
2. Calculation of the composition of the mixture
- Let x be the mass of Na2CO3 and (1 - x) be the mass of NaHCO3 in the mixture.
- Then, we have x(53 / 106) + (1 - x)(84 / 84) = 1
- Solving the equation, we get x = 0.5.
- Therefore, the mixture contains 0.5 g of Na2CO3 and 0.5 g of NaHCO3.
3. Calculation of the equivalent weight of the mixture
- The equivalent weight of the mixture can be calculated as follows:
- Equivalent weight of the mixture = (mass of Na2CO3 / equivalent weight of Na2CO3) + (mass of NaHCO3 / equivalent weight of NaHCO3)
- = (0.5 / 53) + (0.5 / 84)
- = 0.0132 + 0.0059
- = 0.0191 g/equivalent
4. Calculation of the number of equivalents of HCI required for complete neutralisation of the residue
- When the mixture is heated, NaHCO3 decomposes to form Na2CO3, CO2 and H2O.
- Therefore, the residue will contain only Na2CO3.
- Since 1 g of the mixture consumes y equivalents of HCI for complete neutralisation, 0.5 g of Na2CO3 will consume y/2 equivalents of HCI for complete neutralisation.
- When the residue is treated with HCI, the number of equivalents of HCI required for complete neutralisation will be y/2.
Therefore, the correct answer is option B, y equivalents.
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One g of a mixture of Na2CO3 and NaHCO3 consumes y equivalent of HCI for complete neutralisation. One g of the mixture is strongly heated, then cooled and the residue treated with HCI how many equivalent of HCI would be required for com-plete neutralisation? a)2y equivalent b)y equivalent c)3y/4 equivalent d)3y/2 equivalentCorrect answer is option 'B'. Can you explain this answer?
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One g of a mixture of Na2CO3 and NaHCO3 consumes y equivalent of HCI for complete neutralisation. One g of the mixture is strongly heated, then cooled and the residue treated with HCI how many equivalent of HCI would be required for com-plete neutralisation? a)2y equivalent b)y equivalent c)3y/4 equivalent d)3y/2 equivalentCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One g of a mixture of Na2CO3 and NaHCO3 consumes y equivalent of HCI for complete neutralisation. One g of the mixture is strongly heated, then cooled and the residue treated with HCI how many equivalent of HCI would be required for com-plete neutralisation? a)2y equivalent b)y equivalent c)3y/4 equivalent d)3y/2 equivalentCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One g of a mixture of Na2CO3 and NaHCO3 consumes y equivalent of HCI for complete neutralisation. One g of the mixture is strongly heated, then cooled and the residue treated with HCI how many equivalent of HCI would be required for com-plete neutralisation? a)2y equivalent b)y equivalent c)3y/4 equivalent d)3y/2 equivalentCorrect answer is option 'B'. Can you explain this answer?.
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