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Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: [2009]
- a)chlorobenzene
- b)benzylchloride
- c)xylene
- d)toluene
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: ...
Friedel Craft’s reaction.
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Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: ...
Reaction of Benzene with CH3Cl in the Presence of Anhydrous AlCl3
The reaction of benzene with CH3Cl in the presence of anhydrous AlCl3 is a Friedel-Crafts alkylation reaction. The reaction produces toluene as the main product.
Mechanism of the Reaction
The reaction mechanism involves the following steps:
Step 1: Formation of an intermediate carbocation
AlCl3 acts as a Lewis acid and accepts the lone pair of electrons from the chlorine atom of CH3Cl. This creates a carbocation intermediate.
CH3Cl + AlCl3 → CH3+ + AlCl4-
Step 2: Attack of benzene on the carbocation intermediate
The carbocation intermediate formed in step 1 then reacts with benzene. A nucleophilic attack by the pi electron cloud of the benzene ring on the carbocation intermediate results in the formation of a new intermediate.
CH3+ + C6H6 → C6H5CH3+
Step 3: Regeneration of the Lewis acid catalyst
The AlCl4- ion generated in step 1 acts as a Lewis base and accepts a proton from the CH3Cl molecule, thereby regenerating the AlCl3 catalyst.
AlCl4- + CH3Cl → AlCl3 + CH3Cl2-
Overall Reaction
The overall reaction can be represented as follows:
C6H6 + CH3Cl → C6H5CH3 + HCl
Conclusion
The reaction of benzene with CH3Cl in the presence of anhydrous AlCl3 is a Friedel-Crafts alkylation reaction that produces toluene as the main product.
The reaction of benzene with CH3Cl in the presence of anhydrous AlCl3 is a Friedel-Crafts alkylation reaction. The reaction produces toluene as the main product.
Mechanism of the Reaction
The reaction mechanism involves the following steps:
Step 1: Formation of an intermediate carbocation
AlCl3 acts as a Lewis acid and accepts the lone pair of electrons from the chlorine atom of CH3Cl. This creates a carbocation intermediate.
CH3Cl + AlCl3 → CH3+ + AlCl4-
Step 2: Attack of benzene on the carbocation intermediate
The carbocation intermediate formed in step 1 then reacts with benzene. A nucleophilic attack by the pi electron cloud of the benzene ring on the carbocation intermediate results in the formation of a new intermediate.
CH3+ + C6H6 → C6H5CH3+
Step 3: Regeneration of the Lewis acid catalyst
The AlCl4- ion generated in step 1 acts as a Lewis base and accepts a proton from the CH3Cl molecule, thereby regenerating the AlCl3 catalyst.
AlCl4- + CH3Cl → AlCl3 + CH3Cl2-
Overall Reaction
The overall reaction can be represented as follows:
C6H6 + CH3Cl → C6H5CH3 + HCl
Conclusion
The reaction of benzene with CH3Cl in the presence of anhydrous AlCl3 is a Friedel-Crafts alkylation reaction that produces toluene as the main product.
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Community Answer
Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: ...
This reaction is friedal craft Alkylation
and product formed is toluene
and product formed is toluene
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Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: [2009]a)chlorobenzeneb)benzylchloridec)xylened)tolueneCorrect answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: [2009]a)chlorobenzeneb)benzylchloridec)xylened)tolueneCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: [2009]a)chlorobenzeneb)benzylchloridec)xylened)tolueneCorrect answer is option 'D'. Can you explain this answer?.
Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: [2009]a)chlorobenzeneb)benzylchloridec)xylened)tolueneCorrect answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: [2009]a)chlorobenzeneb)benzylchloridec)xylened)tolueneCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: [2009]a)chlorobenzeneb)benzylchloridec)xylened)tolueneCorrect answer is option 'D'. Can you explain this answer?.
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