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A gaseous mixture contains H2 and O2 in the molar ratio 8 : 1. The ratio of H2 : O2 by weight in this mixture would be [1999]
  • a)
    4 : 1
  • b)
    1 : 8
  • c)
    8 : 1
  • d)
    1 : 2
Correct answer is option 'D'. Can you explain this answer?
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A gaseous mixture contains H2 and O2 in the molar ratio 8 : 1. The rat...
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A gaseous mixture contains H2 and O2 in the molar ratio 8 : 1. The rat...
Given: H2 and O2 are in the molar ratio of 8:1 in a gaseous mixture.

To find: The ratio of H2:O2 by weight in the mixture.

Solution:

Let us assume that the total number of moles of the mixture is 'x'. Therefore,

Number of moles of H2 = 8x/9

Number of moles of O2 = x/9

To find the ratio of H2:O2 by weight, we need to find the mass of each gas present in the mixture. Since the ratio of their molecular masses is 2:32, the mass of H2 is 1/16th of the mass of O2.

Therefore, the total mass of H2 in the mixture = (1/17) * (8x/9) * 2 = 16x/153

The total mass of O2 in the mixture = (1/17) * (x/9) * 32 = 32x/153

Hence, the ratio of H2:O2 by weight in the mixture = (16x/153) : (32x/153) = 1:2

Therefore, option D is the correct answer.
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A gaseous mixture contains H2 and O2 in the molar ratio 8 : 1. The ratio of H2 : O2 by weight in this mixture would be [1999]a)4 : 1b)1 : 8c)8 : 1d)1 : 2Correct answer is option 'D'. Can you explain this answer?
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