Calculate the % of O2 in the gaseous mixture:
1. By Mass:
Given:
- Mass of the gaseous mixture = 1g
- Volume of the gaseous mixture = 600ml
- Molar mass of O2 = 32g/mol
- Molar mass of O3 = 48g/mol
Calculate the moles of O2 and O3 in the mixture using the molar masses:
- Moles of O2 = mass/molar mass = 1g/32g/mol = 0.03125 mol
- Moles of O3 = moles of O2 (as they are in a 1:1 ratio)
Calculate the mass of O2 and O3 in the mixture:
- Mass of O2 = moles of O2 * molar mass of O2 = 0.03125 mol * 32g/mol = 1g
- Mass of O3 = 1g - 1g = 0g
Calculate the % of O2 by mass:
- % of O2 = (mass of O2 / total mass of mixture) * 100
- % of O2 = (1g/1g) * 100 = 100%
2. By Mole:
Given:
- Moles of O2 = 0.03125 mol
- Moles of O3 = 0.03125 mol
Calculate the % of O2 by mole:
- % of O2 = (moles of O2 / total moles of mixture) * 100
- % of O2 = (0.03125 mol / 0.0625 mol) * 100 = 50%
3. By Volume:
Given:
- Volume of the gaseous mixture = 600ml
- At STP, 1 mole of gas occupies 22.4L
Calculate the moles of the gaseous mixture:
- Moles of the mixture = volume/22.4L = 0.6L/22.4L = 0.02679 mol
Calculate the volume of O2 and O3 in the mixture:
- Volume of O2 = moles of O2 * 22.4L = 0.03125 mol * 22.4L = 0.7L
- Volume of O3 = 0.6L - 0.7L = -0.1L
Since the volume of O3 is negative, it indicates an error in the calculation. This suggests that the assumption of a 1:1 mixture of O2 and O3 may not be correct, and further analysis is needed.