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A solution containing 2.675g of CoCI3.6NH3 (molar mass=267.5 g mol-1) is passed through a cation exchanger. Thechloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCI (molar mass = 143.5 g mol-1). The formula of the complex is:(At. mass of Ag =108 u)a)[CoCI(NH3)5]CI2 b)[Co(NH3)6]CI3 c)[CoCI2(NH3)4]CId)[CoCI3(NH3)3]Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A solution containing 2.675g of CoCI3.6NH3 (molar mass=267.5 g mol-1) is passed through a cation exchanger. Thechloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCI (molar mass = 143.5 g mol-1). The formula of the complex is:(At. mass of Ag =108 u)a)[CoCI(NH3)5]CI2 b)[Co(NH3)6]CI3 c)[CoCI2(NH3)4]CId)[CoCI3(NH3)3]Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution containing 2.675g of CoCI3.6NH3 (molar mass=267.5 g mol-1) is passed through a cation exchanger. Thechloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCI (molar mass = 143.5 g mol-1). The formula of the complex is:(At. mass of Ag =108 u)a)[CoCI(NH3)5]CI2 b)[Co(NH3)6]CI3 c)[CoCI2(NH3)4]CId)[CoCI3(NH3)3]Correct answer is option 'B'. Can you explain this answer?.

Solutions for A solution containing 2.675g of CoCI3.6NH3 (molar mass=267.5 g mol-1) is passed through a cation exchanger. Thechloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCI (molar mass = 143.5 g mol-1). The formula of the complex is:(At. mass of Ag =108 u)a)[CoCI(NH3)5]CI2 b)[Co(NH3)6]CI3 c)[CoCI2(NH3)4]CId)[CoCI3(NH3)3]Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

Here you can find the meaning of A solution containing 2.675g of CoCI3.6NH3 (molar mass=267.5 g mol-1) is passed through a cation exchanger. Thechloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCI (molar mass = 143.5 g mol-1). The formula of the complex is:(At. mass of Ag =108 u)a)[CoCI(NH3)5]CI2 b)[Co(NH3)6]CI3 c)[CoCI2(NH3)4]CId)[CoCI3(NH3)3]Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A solution containing 2.675g of CoCI3.6NH3 (molar mass=267.5 g mol-1) is passed through a cation exchanger. Thechloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCI (molar mass = 143.5 g mol-1). The formula of the complex is:(At. mass of Ag =108 u)a)[CoCI(NH3)5]CI2 b)[Co(NH3)6]CI3 c)[CoCI2(NH3)4]CId)[CoCI3(NH3)3]Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A solution containing 2.675g of CoCI3.6NH3 (molar mass=267.5 g mol-1) is passed through a cation exchanger. Thechloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCI (molar mass = 143.5 g mol-1). The formula of the complex is:(At. mass of Ag =108 u)a)[CoCI(NH3)5]CI2 b)[Co(NH3)6]CI3 c)[CoCI2(NH3)4]CId)[CoCI3(NH3)3]Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A solution containing 2.675g of CoCI3.6NH3 (molar mass=267.5 g mol-1) is passed through a cation exchanger. Thechloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCI (molar mass = 143.5 g mol-1). The formula of the complex is:(At. mass of Ag =108 u)a)[CoCI(NH3)5]CI2 b)[Co(NH3)6]CI3 c)[CoCI2(NH3)4]CId)[CoCI3(NH3)3]Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A solution containing 2.675g of CoCI3.6NH3 (molar mass=267.5 g mol-1) is passed through a cation exchanger. Thechloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCI (molar mass = 143.5 g mol-1). The formula of the complex is:(At. mass of Ag =108 u)a)[CoCI(NH3)5]CI2 b)[Co(NH3)6]CI3 c)[CoCI2(NH3)4]CId)[CoCI3(NH3)3]Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.