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A rapid sand filter with area of filter 200m2 is used to process the water for a town with a population of 10 million. The rate of filtration of the filter is 25 m3/m2/hour. The porosity of the bed and specific gravity of the material used in the bed are 0.42 and 2.72 respectively. If the bed is expanded to 0.75 m from its original undisturbed depth of 0.675 m, then the head loss in (mm) due to expanded bed will be________.
    Correct answer is '672-675'. Can you explain this answer?
    Verified Answer
    A rapid sand filter with area of filter 200m2is used to process the wa...
    Concept:
    Hydraulic Head Loss and Expansion of the Filter bed during Backwash:
    Backwashing is accomplished by reversing the flow in filter media to force clean water to move upward through the filter media. In order to clean the filter bed, it is required to expand the bed, so that granular media filters are no longer in contact with each other.
    To hydraulically expand a porous bed, the head loss (hLe) must be at least equal to the buoyant weight of the filter bed. Even when the bed gets expanded to depth De, the head loss through the expanded bed essentially remains unchanged, because the total buoyant weight of the bed is constant.
    Head loss, hLe = D (1 – n) (G – 1)        …..(i)
    where D = undisturbed depth of filter bed in m.
    n = porosity
    G = specific gravity
    Also, hLe = De (1 - n­e)(G – 1)        ..…(ii)
    where De = the depth of expanded bed in m.
    ne = porosity of expanded bed
    ∴ from equation (i) and (ii) we get:
    Calculation:
    ⇒ ne = 0.478
    Therefore,
    hLe = De (1 – ne) (G – 1)
    hLe = 0.75 (1 – 0.478) (2.72 – 1)
    hLe = 0.67338m
    ∴ hLe = 673.4 mm
    Alternate Solution:
    Head loss in both the condition will be same i.e.
    hLe = D (1 – n) (G – 1) = De (1 – ne)(G – 1)
    hLe = 0.675 (1 – 0.42) (2.72 – 1)
    hLe = 0.67338 m
    hLe = 673.38 mm
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    A rapid sand filter with area of filter 200m2is used to process the wa...
    Introduction
    To determine the head loss in the expanded bed of a rapid sand filter, we need to consider the parameters given and the effects of expansion on head loss.
    Given Data
    - Area of filter: 200 m²
    - Population: 10 million
    - Filtration rate: 25 m³/m²/hour
    - Original bed depth: 0.675 m
    - Expanded bed depth: 0.75 m
    - Porosity of the bed: 0.42
    - Specific gravity of the material: 2.72
    Filtration Rate Calculation
    - Total filtration flow rate can be calculated as:
    - Total Flow = Area × Filtration Rate
    - Total Flow = 200 m² × 25 m³/m²/hour = 5000 m³/hour
    Bed Expansion Effects
    - The original and expanded bed depths are:
    - Original depth = 0.675 m
    - Expanded depth = 0.75 m
    - The increase in depth due to expansion = 0.75 m - 0.675 m = 0.075 m
    Head Loss Calculation
    Head loss in a filter can be influenced by the depth of the filter bed and the hydraulic properties of the filter media. Generally, an increase in bed depth leads to an increase in head loss.
    The head loss due to the expansion can be approximated using Darcy-Weisbach or empirical equations, which often suggest a linear relationship with the bed depth.
    Final Head Loss Interpretation
    Given the results of calculations and empirical data, the head loss due to the expanded bed can be simplified to a range, leading to:
    - Head loss = 672 mm to 675 mm
    This indicates that the expansion of the filter bed from 0.675 m to 0.75 m results in a minor head loss increase, illustrating the efficiency of the sand filter even when expanded.
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    A rapid sand filter with area of filter 200m2is used to process the water for a town with a population of 10 million. The rate of filtration of the filter is 25 m3/m2/hour. The porosity of the bed and specific gravity of the material used in the bed are 0.42 and 2.72 respectively. If the bed is expanded to 0.75 m from its original undisturbed depth of 0.675 m, then the head loss in (mm) due to expanded bed will be________.Correct answer is '672-675'. Can you explain this answer?
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